Semiconductor doping — effect of pentavalent (donor) impurities When a pentavalent impurity (for example, phosphorus, arsenic, or antimony) is added to a pure semiconductor crystal, the resulting semiconductor becomes:
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Ap-type
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Bn-type
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CIntrinsic (undoped)
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DElectrically neutral with no change in carriers
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EDegenerate p-type
Answer
Correct Answer: n-type
Explanation
Introduction / Context:Doping controls carrier type and concentration in semiconductors. Pentavalent dopants in group-IV semiconductors provide extra electrons near the conduction band and are central to forming n-type regions in diodes and transistors.
Given Data / Assumptions:
- Host crystal: group-IV (e.g., Si, Ge).
- Dopant valence: 5 (donor), such as P, As, Sb.
- Low to moderate doping so the material remains nondegenerate.
Concept / Approach:Pentavalent atoms substitute for a host atom and form four covalent bonds, leaving one loosely bound electron. This donor electron is thermally ionized at room temperature, contributing a free electron to the conduction band and creating a positively charged donor ion. Thus electrons become majority carriers and the material is n-type.
Step-by-Step Solution:Identify dopant valence: 5 → donor.Ionization releases an electron to the conduction band.Carrier balance shifts: n ≫ p → n-type behavior.
Verification / Alternative check:Energy band diagrams show donor levels slightly below the conduction band; at room temperature most donors are ionized, raising electron concentration.
Why Other Options Are Wrong:p-type requires acceptors (trivalent B, Al, Ga). “Intrinsic” ignores the dopant. “Neutral with no change” is false; carrier concentration changes markedly. “Degenerate p-type” is unrelated to donor doping.
Common Pitfalls:
- Confusing donor and acceptor terminology.
- Assuming all dopants create the same carrier type.
Final Answer:n-type