Saturable reactor behavior When the magnetic core of a saturable reactor is driven into saturation, what happens to its inductance?

Difficulty: Easy

Correct Answer: False

Explanation:


Introduction / Context:
Saturable reactors exploit the nonlinear magnetization of a core to control effective inductance with a DC control current. Understanding how inductance changes near saturation is crucial for control and protection.



Given Data / Assumptions:

  • Inductance L ∝ μ (effective permeability) for a given geometry.
  • Core B–H curve shows μ dropping significantly in saturation.


Concept / Approach:
As the core approaches saturation, incremental permeability decreases sharply, which reduces the incremental inductance. Therefore, in saturation, the inductive reactance drops, allowing more AC current to flow—this is the very principle used in magnetic amplifiers and saturable reactors.



Step-by-Step Solution:
Unsaturated: μ is high ⇒ L is high.Drive into saturation: μ falls ⇒ L falls.Hence, the statement “inductance is high in saturation” is false.



Verification / Alternative check:
Differential inductance measured from the slope of the B–H curve near saturation is small, matching the expected drop.



Why Other Options Are Wrong:
Inductance infinite/unchanged: Not supported by magnetic material physics.
“True” to the original claim: Opposite of actual behavior.



Common Pitfalls:
Confusing unsaturated high-μ behavior with the saturated regime; they are opposite in effect on L.



Final Answer:
False

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