Difficulty: Easy
Correct Answer: latch
Explanation:
Introduction / Context:An output port is the hardware point where a processor's internal data bus hands data off to the outside world (LEDs, relays, DACs, and so on). The circuit used must capture the value during a write cycle and hold it stable long after the bus has moved on to other operations.
Given Data / Assumptions:
Concept / Approach:A transparent latch or an edge-triggered register captures data from the data bus when the write strobe and the address decoder indicate an addressed write. After the brief write, the bus releases the data lines, but the latch continues to drive the external pins with the stored value. This separation of capture and hold action is the essence of an output port.
Step-by-Step Solution:
Use address decoding to generate a chip-select pulse for the chosen output port.Combine chip-select with WR to produce a load enable for the latch.On the active load, the latch stores D7..D0 (or the bus width).Between writes, the latch holds the output stable so the field device sees a continuous logic level.Verification / Alternative check:Observe with a logic analyzer: bus data exists only for the write window, yet the port pin stays at the written level afterwards—proof that storage (latching) is occurring.
Why Other Options Are Wrong:
Common Pitfalls:Confusing input and output port hardware: inputs typically use tristate buffers to place data onto the bus only when selected, while outputs require storage to maintain levels.
Final Answer:latch
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