Directions: Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statements is/are necessary to answer the question. What is the present age of Tanya ? I. The ratio between the present ages of Tanya and her brother Rahul is 3 : 4 respectively. II. After 5 years the ratio between the ages of Tanya and Rahul will be 4 : 5. III. Rahul is 5 years older than Tanya.
Aptitude
Problems on Ages
Difficulty: Easy
Choose an option
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AI and II only
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BII and III only
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CI and III only
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DAll I, II and III
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EAny two of the three
Answer
Correct Answer: Any two of the three
Explanation
### Concept & Logic
This is a two-variable problem involving Tanya ($T$) and Rahul ($R$). To find $T$, we need two independent conditions.
### Step-by-Step Solution
Let's evaluate the statements by pairing them:
* **Statement I:** $T : R = 3 : 4$
* **Statement II:** $(T + 5) : (R + 5) = 4 : 5$
* **Statement III:** $R - T = 5$
* **Using I and II:**
Let present ages be $3x$ and $4x$. After 5 years: $\frac{3x + 5}{4x + 5} = \frac{4}{5}$.
$15x + 25 = 16x + 20 \Rightarrow x = 5$.
Tanya's age = $3 \times 5 = 15$. (Sufficient)
* **Using II and III:**
Let ages after 5 years be $4y$ and $5y$. The difference in ages is always constant.
From III, difference is 5. So, $5y - 4y = 5 \Rightarrow y = 5$.
Tanya's age in 5 years = $4 \times 5 = 20$. Present age = $20 - 5 = 15$. (Sufficient)
* **Using I and III:**
Let present ages be $3z$ and $4z$.
From III, difference is 5. So, $4z - 3z = 5 \Rightarrow z = 5$.
Tanya's age = $3 \times 5 = 15$. (Sufficient)
### Exam Strategy & Shortcut
**Cross-Verification Shortcut:** Notice that Statement III ($R - T = 5$) is essentially the derived difference from the ratios in I ($3:4 \rightarrow$ difference of 1 unit) and II ($4:5 \rightarrow$ difference of 1 unit). Because all three statements are mathematically consistent and independent in pairs, any two will trigger the solution. No need to calculate all three pairs in the exam!
### Common Pitfall
A common mistake is assuming that because Statement III looks simpler, it must be paired with a ratio, leading students to choose "I and III only" or "II and III only" while ignoring that the two ratios (I and II) combined also perfectly solve the problem.
### Final Answer
**Therefore, the correct answer is Any two of the three.**