Difficulty: Easy
Correct Answer: 1 x 10^-7
Explanation:
Introduction / Context:
Converting between pH and [H+] is a routine skill. At 25 °C for pure water, pH 7 corresponds to neutral conditions where [H+] equals [OH–].
Given Data / Assumptions:
Concept / Approach:
Rearrange pH definition: [H+] = 10^(-pH). Substitute pH = 7 to obtain [H+] = 10^-7 mol/L.
Step-by-Step Solution:
Start with pH = −log10[H+].
Take antilog: [H+] = 10^(-pH).
Plug pH 7: [H+] = 10^-7 mol/L.
Therefore, the correct numerical value is 1 x 10^-7 mol/L.
Verification / Alternative check:
Using Kw = [H+][OH–] = 1.0 x 10^-14 and [H+] = [OH–] at neutrality also yields [H+] = 1.0 x 10^-7 mol/L.
Why Other Options Are Wrong:
Options with 7 or 7 x 10^-7 are incorrect manipulations; 5 x 10^-7 is arbitrary; 1 x 10^-5 corresponds to pH 5, not 7.
Common Pitfalls:
Forgetting the negative sign in the definition, misplacing the exponent by one or two orders of magnitude.
Final Answer:
1 x 10^-7.
Discussion & Comments