Difficulty: Easy
Correct Answer: Its conjugate base
Explanation:
Introduction / Context:
The Bronsted–Lowry definition classifies acids as proton donors and bases as proton acceptors. Tracking the species before and after proton transfer clarifies buffering, titration, and enzymatic acid–base catalysis.
Given Data / Assumptions:
Concept / Approach:
When HA donates H+, it becomes A−, which is called the conjugate base of HA. Simultaneously, the acceptor (for example, H2O) becomes its conjugate acid (H3O+). This reciprocal relationship underlies buffer action: both members of a conjugate pair coexist near pKa.
Step-by-Step Solution:
Write a generic reaction: HA + H2O → A− + H3O+.Identify donor: HA (acid). After donation, HA → A−.Name A− as the conjugate base of HA.
Verification / Alternative check:
Acetic acid/acetic base pair: CH3COOH ⇌ CH3COO− + H+. The acetate ion is the conjugate base.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing the identities of conjugate pairs; always compare species that differ by one proton.
Final Answer:
Its conjugate base.
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