Difficulty: Easy
Correct Answer: Purple (deep violet due to crystal violet–iodine complex)
Explanation:
Introduction / Context:
The Gram stain is the most widely used differential stain in bacteriology. It rapidly separates clinical isolates into two major groups based on their cell wall structure. Correct colour recognition is essential for immediate reporting and guides empirical therapy and further testing.
Given Data / Assumptions:
Concept / Approach:
Gram-positive cell walls have a thick peptidoglycan layer with extensive crosslinking and teichoic acids. During the staining, the crystal violet–iodine complex forms large aggregates that are physically trapped within this thick matrix. When alcohol/acetone is applied, Gram-positive walls shrink and retain the complex, whereas Gram-negative outer membranes are disrupted and their thin peptidoglycan fails to retain the dye, accepting the counterstain instead.
Step-by-Step Solution:
Apply crystal violet → all cells appear violet.
Add iodine → forms an insoluble crystal violet–iodine complex.
Decolorize → Gram-positive retain complex; Gram-negative lose it.
Counterstain with safranin → Gram-negative appear pink; Gram-positive remain purple.
Verification / Alternative check:
Controls: Staphylococcus aureus (Gram-positive) should appear purple; Escherichia coli (Gram-negative) should appear pink. Including controls validates technique and decolorization time.
Why Other Options Are Wrong:
Common Pitfalls:
Over- or under-decolorizing can misclassify organisms. Old cultures of Gram-positive bacteria may appear Gram-variable; always use fresh controls.
Final Answer:
Purple (deep violet due to crystal violet–iodine complex).
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