Difficulty: Easy
Correct Answer: A mixture of ethyl alcohol and acetone (acetone-alcohol)
Explanation:
Introduction / Context:
The critical step in the Gram stain is decolorization, which differentiates Gram-positive from Gram-negative organisms. The choice and timing of decolorizer profoundly affect results and are standardized in most clinical labs.
Given Data / Assumptions:
Concept / Approach:
Many protocols employ acetone–alcohol mixtures (commonly 1:1 acetone:ethanol) because they provide rapid, consistent decolorization. Pure ethanol or pure acetone can be used, but the mixture balances speed and control, reducing the risk of over- or under-decolorization compared with a single solvent in routine practice.
Step-by-Step Solution:
After iodine mordant, apply acetone-alcohol briefly.
Gram-positive retain the crystal violet–iodine complex; Gram-negative are decolorized.
Counterstain, then read purple (Gram+) vs pink (Gram−).
Verification / Alternative check:
Quality control with known Gram-positive and Gram-negative organisms ensures decolorizer performance and correct timing.
Why Other Options Are Wrong:
Common Pitfalls:
Excessive exposure leads to false Gram-negative results; insufficient exposure yields false Gram-positive results.
Final Answer:
The common decolorizer is a mixture of ethyl alcohol and acetone (acetone-alcohol).
Discussion & Comments