Gram decolorization step: Which reagent is most commonly used as the decolorizer in the Gram staining procedure?

Difficulty: Easy

Correct Answer: A mixture of ethyl alcohol and acetone (acetone-alcohol)

Explanation:


Introduction / Context:
The critical step in the Gram stain is decolorization, which differentiates Gram-positive from Gram-negative organisms. The choice and timing of decolorizer profoundly affect results and are standardized in most clinical labs.



Given Data / Assumptions:

  • Standard four-step Gram procedure is used.
  • We must choose the reagent most commonly applied as the decolorizer.



Concept / Approach:
Many protocols employ acetone–alcohol mixtures (commonly 1:1 acetone:ethanol) because they provide rapid, consistent decolorization. Pure ethanol or pure acetone can be used, but the mixture balances speed and control, reducing the risk of over- or under-decolorization compared with a single solvent in routine practice.



Step-by-Step Solution:
After iodine mordant, apply acetone-alcohol briefly. Gram-positive retain the crystal violet–iodine complex; Gram-negative are decolorized. Counterstain, then read purple (Gram+) vs pink (Gram−).



Verification / Alternative check:
Quality control with known Gram-positive and Gram-negative organisms ensures decolorizer performance and correct timing.



Why Other Options Are Wrong:

  • Ethanol alone / Acetone alone: Usable but less commonly standardized than the mixture in many labs.
  • Methyl alcohol / Isopropanol only: Not the typical decolorizers in standard protocols.



Common Pitfalls:
Excessive exposure leads to false Gram-negative results; insufficient exposure yields false Gram-positive results.



Final Answer:
The common decolorizer is a mixture of ethyl alcohol and acetone (acetone-alcohol).


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