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Syllogism: Determine which conclusions must follow from the chain of containments. Statements: All the pencils are pens. All the pens are inks. Conclusions: I. All the pencils are inks. II. Some inks are pencils. Choose the correct option about which conclusion(s) follow.

Difficulty: Easy

Correct Answer: Both Conclusions I and II follow

Explanation:


Given data

  • All pencils ⊆ pens; All pens ⊆ inks ⇒ All pencils ⊆ inks.
  • Conclusions: (I) All pencils are inks; (II) Some inks are pencils.


Concept/Approach
Transitivity of containment validates I. Under standard MCQ convention assuming existence of pencils, at least one pencil exists, so that element is an ink; hence "Some inks are pencils" holds.


Step-by-step evaluation
I: Directly true by transitivity (pencils ⊆ inks). II: From existence of at least one pencil in the subset, "some" particular of inks is indeed a pencil.


Final Answer
Both Conclusions I and II follow

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