Number series (find the wrong term): 3, 10, 27, 4, 16, 64, 5, 25, 125

Introduction / Context:
Error-spotting in series often uses mini-patterns that repeat. Here, numbers are grouped in triplets with a clear base–square–cube relationship. One value in the first triplet does not match the rule.

Given Data / Assumptions:

• Series: 3, 10, 27, 4, 16, 64, 5, 25, 125.
• Exactly one term is wrong.
• Triplet idea: (n, n^2, n^3) for successive bases n.

Concept / Approach:
Group the terms: (3, 10, 27), (4, 16, 64), (5, 25, 125). In a correct pattern, each triplet should be base, base^2, base^3.

Step-by-Step Solution:
Triplet 1 expected: 3, 9, 27 (since 3^2=9 and 3^3=27).Given: 3, 10, 27 → the middle term should be 9, not 10.Triplet 2: 4, 16, 64 is correct (4^2=16, 4^3=64).Triplet 3: 5, 25, 125 is correct (5^2=25, 5^3=125).

Verification / Alternative check:
Replacing 10 by 9 makes each triplet perfect base–square–cube blocks, removing the sole inconsistency.

Why Other Options Are Wrong:

• 3, 4, 27, 25 all fit their respective base, square, and cube roles in the observed pattern.

Common Pitfalls:

• Not noticing the 3-term repeating motif and instead searching for a single-step recurrence across all nine terms.

Final Answer:
10