A is two years older than B and B is twice as old as C. If A + B + C = 27 years, how old is B?

Problem restatementRelate A, B, and C using the given age differences and total, then solve for B.

Given data

• A = B + 2
• B = 2C
• A + B + C = 27

Concept/ApproachExpress everything in terms of C and substitute into the total.

Step-by-step calculation B = 2C;  A = 2C + 2 (2C + 2) + 2C + C = 27 5C + 2 = 27 → 5C = 25 → C = 5 B = 2C = 10

VerificationA = 12, B = 10, C = 5; sum = 27 (consistent).

Common pitfalls

• Taking A = 2B by mistake; the statement is A is two years older than B, not twice as old.

Final Answer10 years