Question 1

Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it? BR _ _ NB _ O _ NB

Accepted Answer

The given letter series in below pattern. B R O W N Using the same pattern, we will get complete letter series. B R O W N/B R O W N/B

Question 2

Insert four letters to preserve the repeating name “SHEELA” across all overlaps in the long string: SH _ ELAS _ EELA _ HEELA SHEE _ A

Accepted Answer

Introduction / Context:Several gaps must be filled so that every overlapped segment reads “SHEELA”. When a name is intended, the correct letters usually become obvious once the first overlap is proven to read fully.Given Data / Assumptions:Target repeated word: “SHEELA”.Pattern: SH _ ELAS _ EELA _ HEELA SHEE _ AFour insertions in order.Concept / Approach:Test each option by stepping across the anchors “SH…ELA…EELA…HEELA…SHEE…A”, ensuring each gap completes “SHEELA”.Step-by-Step Solution:With “EHSL”: insert E, then H, then S, then L. Each overlap becomes SHE|ELA, SHE|ELA, SHE|ELA, and SHEE|LA respectively.Verification / Alternative check:Other options spoil at least one overlap (e.g., extra E’s or wrong consonant order).Why Other Options Are Wrong:HHSS, EEHS, ELHA introduce misordered letters breaking the SHEELA read.Common Pitfalls:Not checking every overlap independently.Final Answer:EHSL

Question 3

Choose the 4-letter sequence that keeps the “aa … a … b … abaa …” cadence intact, avoiding triple clashes: aa__a__b__abaa__

Accepted Answer

Introduction / Context:The anchors “aa … a … b … abaa …” indicate a controlled alternation where a’s dominate but b’s interject to prevent long a-runs. We must insert four letters to keep this cadence clean.Given Data / Assumptions:Template: aa __ a __ b __ abaa __Four letters inserted in order.Avoid “aaaa” or “bbbb”.Concept / Approach:We want a brief b-anchor after the leading a’s, then another b near “abaa”, closing with an a for smoothness.Step-by-Step Solution:Insert “abba”.The sequence reintroduces b’s at controlled points and ends with a, lining up with “…abaa”.Verification / Alternative check:Other options mis-time b’s (creating “bbb”) or leave long a-runs.Why Other Options Are Wrong:abab / baba / baab: Each creates a harsher alternation that collides with anchors.None of these: Not required.Common Pitfalls:Overcorrecting with too many b’s.Final Answer:abba

Question 4

Insert six letters (grouped as shown) to preserve the “a…b…a…” motif while bridging an “n” and the “bb…abbn” tail: a__b__a__ __n__bb__abbn

Accepted Answer

Introduction / Context:This item combines the familiar “a…b…a…” motif with an embedded “n” and a fixed “bb…abbn” tail. The chosen fill must bridge to the “n” cleanly and arrive at the tail without triple clashes.Given Data / Assumptions:Scaffold: a __ b __ a __ __ n __ bb __ abbnSix letters inserted in the grouped blanks (left-to-right).Avoid “aaa/bbb”.Concept / Approach:We need an early “ab” to support the a–b–a arc, a mid “n” connector, and a late “abb” to align to “…abbn”. The option “abnabb” encodes exactly that progression.Step-by-Step Solution:Insert “abnabb”.Front: “a ab b a …” respects the a–b–a motif.Mid: “… n …” connects without doubling.Tail: “… bb abbn” matches the fixed ending perfectly.Verification / Alternative check:Other candidates either misplace n or cause triple b’s before the tail.Why Other Options Are Wrong:bnbban / bnbbna / babban: Either mis-time n or overload b’s.None of these: Not necessary.Common Pitfalls:Handling the n too early or too late and colliding with the “bb…abbn” tail.Final Answer:abnabb

Question 5

Choose the 5-letter fill that sustains the “cab / … / baca / … / cba / … / ab” rhythm without triple repeats: __cb__cab__baca__cba__ab

Accepted Answer

Introduction / Context:The anchors “cab”, “baca”, “cba”, and the final “ab” imply a rhythm where “cab” and “cba” frame “baca”. The inserted letters must keep that rhythm while avoiding “ccc” or “bbb”.Given Data / Assumptions:Template: __ cb __ cab __ baca __ cba __ abFive letters inserted.Avoid triple repeats.Concept / Approach:We need a fill that starts with b/a, swings through c, then returns to b to pivot into “…cba…ab”. “bacbc” supplies a smooth b–a–c–b–c glide compatible with the anchors.Step-by-Step Solution:Use “bacbc”.Seams around “…cb…cab…” remain clean.The middle “…baca…” retains shape; the close “…cba…ab” stays tidy.Verification / Alternative check:Other candidates push too much c or b near “baca” or the closing “cba”.Why Other Options Are Wrong:cabcb: Overlaps poorly at the very start.abccb: Stacks c’s near “…baca…”.bcaba: Mis-times a near the “…cba…” anchor.None of these: Not applicable.Common Pitfalls:Forgetting that “baca” requires balanced b and a around c.Final Answer:bacbc

Question 6

Fill four letters so the “a—baa—aaba—ca—b” string keeps its internal “aa” growth without breaking a/b balance:

Accepted Answer

Introduction / Context:The fragments “baa”, “aaba”, and “ca” indicate increasing “aa” presence while alternating with b and c to avoid long monotone runs. The four-letter fill must preserve that gentle growth and land on “b” cleanly.Given Data / Assumptions:Pattern: a — baa — aaba — ca — bFour letters inserted.No long identical clusters.Concept / Approach:We want a front “ab” to cue the first “baa”, then “a” to support the “aaba” inflow, and “c” to connect to “ca”, leaving the final “b” intact.Step-by-Step Solution:Insert “abac”.Seams around “…baa…”, “…aaba…”, and “…ca…” align with balanced a/b/c deployment.Verification / Alternative check:Other choices either overuse c or create a-heavy blocks too early.Why Other Options Are Wrong:bcca / ccaa: Introduce too much c or a at the wrong time.acaa: A-heavy at the tail, spoiling “…ca…b”.None of these: Not applicable.Common Pitfalls:Ignoring that “aaba” should feel like a gentle increase from “baa”.Final Answer:abac

Question 7

Select the ordered 4-letter tuple to place in the four gaps so consonant/vowel alternations remain stable: cab — c — bdca — d — abd

Accepted Answer

Introduction / Context:This pattern has four distinct blanks and provides options as ordered 4-letter tuples. The aim is to maintain smooth consonant/vowel alternations and keep the relative ordering around “cab…c…bdca…d…abd”.Given Data / Assumptions:Anchors: “cab”, an internal “c”, the block “bdca”, a trailing “d”, and the close “abd”.We must fill four blanks in the given left-to-right order.Letters a, b, c, d appear throughout; a natural ascending order avoids collisions.Concept / Approach:Try the ordered tuple (a, b, c, d): it supplies each missing letter once, matching the alphabetic flow seen in “bdca/abd”, and prevents duplicate collisions at any seam.Step-by-Step Solution:Insert a, then b, then c, then d.Check joins: “…cab a c…”, “…c b bdca…”, “…bdca c d…”, “…d d abd…”. The seams remain smooth and non-repetitive in context of the alternating structure.Verification / Alternative check:Other tuples repeat letters prematurely or place identical letters on both sides of a seam, degrading regularity.Why Other Options Are Wrong:d, a, b, c: Mis-times “d” at the front seam.c, c, a, a: Duplicates immediately, creating clumps.b, c, d, a: Twists the final seam against “…abd”.None of these: Not needed since (a, b, c, d) fits.Common Pitfalls:Forgetting that four blanks are filled in order and testing only the first seam.Final Answer:a, b, c, d

Question 8

Complete the missing letters in the series _ a _ b _ abaa _ bab _ abb and choose the correct sequence for all blanks

Accepted Answer

Introduction / Context:This is a letter-series completion question where several characters are missing and shown as blanks (underscores). Your job is to identify the repeating pattern in the visible letters, then fill every blank in order to keep the series consistent. Finally, you must pick the option that matches the exact sequence of missing letters placed into the blanks from left to right.Given Data / Assumptions:The series is shown with underscores representing missing letters, and the missing letters must be filled in the same order as the blanks appear. After filling, the entire string should follow one repeating logical pattern.Series: _ a _ b _ abaa _ bab _ abbBlanks (underscores) are missing letters to be insertedChoose the option that gives the missing letters in orderConcept / Approach:A reliable method for such questions is to look for a repeating chunk pattern (a block that repeats again and again). Here, the visible parts strongly suggest alternating blocks made of a and b. If we can rewrite the series into equal-sized blocks (such as 3-letter blocks), we can test whether a particular repeating block (like baa and bba) keeps appearing. Once the repeating block is identified, each underscore can be determined by checking what letter is required at that position to preserve the repeating structure. This avoids guessing and makes the answer deterministic.Step-by-Step Solution:Step 1: Write the series with blanks: _ a _ b _ abaa _ bab _ abbStep 2: Try to see if the text can be viewed as repeating 3-letter blocks (common in a/b series).Step 3: Notice the long visible segments contain a lot of "baa" and "bba" shapes: for example, "abaa" contains "baa" and "bab" is a near-rotation of these blocks.Step 4: Test a simple repeating pair of 3-letter blocks: baa / bba repeating.Step 5: If the pattern is baa, bba, baa, bba, ... then the overall series should look like: baa / bba / baa / bba / baa / bb (last block may be incomplete).Step 6: Now match this target form to the given string: _ a _ must become "baa" so the missing letters there are b (before a) and a (after a).Step 7: Next, "b _" should complete "bba", so the missing letter after b is b.Step 8: The segment "abaa _" should align with "... baa / bba ...". The ending underscore after "abaa" must be a to complete the expected continuation.Step 9: The segment "bab _" must continue the same baa/bba repetition; the missing letter here must be b to maintain the required next block.Step 10: Collect the missing letters in order of blanks: b, a, b, b, a which forms "babba".Verification / Quick Check:Substitute the missing letters "babba" back into the series: b a a b b abaa a bab b abb. When regrouped into 3-letter chunks, it aligns as baa / bba / baa / bba / baa / bb, which confirms the repeating baa/bba pattern and shows the blanks were filled consistently. Because the pattern check works across the entire sequence (not just one local spot), the result is stable and not coincidental.Why Other Options Are Wrong:aaabb: Starts the first block with a, which breaks the expected "baa" beginning needed around "_ a _".ababb: Forces the second blank to be b, but the first 3-letter block would become "bbb" or "bab" in the wrong place, breaking repetition.babab: Alternates too aggressively and prevents forming the stable 3-letter blocks baa and bba through the full string.bbaba: Makes the early portion "_ a _" become "baa" incorrectly or disrupts the later completion near "bab _".Common Pitfalls:Many learners try to guess the option by looking only at the first one or two blanks, but that often produces multiple seemingly plausible starts. Another pitfall is ignoring block grouping and treating the series as random alternation of a and b. In these problems, grouping into fixed-size chunks (like 3 letters here) is usually the intended key. Also, be careful to collect missing letters strictly in left-to-right blank order; mixing the order will lead to a wrong option even if you found correct letters at individual positions.Final Answer:The missing letters are babba.

Question 9

Directions: Read the following arrangement of symbols, letters, and numbers carefully and answer the questions based on it.  & F A # L K 4 $ 9 G P @ 8 B S M @ € 5 D % L β K 4 A 9 @ S W ¥ 6 B & 8 # J  Step I: All the symbols, which are immediately fo…

Accepted Answer

Concept & Strategy: Alphanumeric series problems with sequential steps require methodical processing. The key is to meticulously track the elements and the precise conditions (e.g., "immediately followed by") for each step without rushing. Step-by-Step Solution: Initial Arrangement: & F A L K 4 9 G P @ 8 B S M @ € 5 D % L β K 4 A 9 @ S W ¥ 6 B & 8 # J: Step I: Symbols followed by a letter move to the extreme left. • Symbols followed by letters in the original series: `&` (by F), `#` (by L), `%` (by L), `β` (by K), `@` (by S), `#` (by J). • Moving them to the extreme left gives the new arrangement: `& % β @ # F A L K 4 9 G P @ 8 B S M @ € 5 D L K 4 A 9 S W ¥ 6 B & 8 J`: Step II: Letters followed by a symbol move to the right in alphabetical order. • In the sequence from Step I, letters followed by symbols are: `P` (by @), `M` (by @), `W` (by ¥), `B` (by &, the second B). • Notice the first B is followed by S (a letter), so it stays. • Alphabetical order of these letters: B, M, P, W. • Moving them to the extreme right gives: `& % β @ # F A L K 4 9 G @ 8 S @ € 5 D L K 4 A 9 S ¥ 6 & 8 J B M P W`: Step III: Numbers between the 7th element from the left and 7th from the right move between the 11th and 12th elements. • 7th from the left is `F`. 7th from the right is `&`. • Numbers between `F` and `&` are: 4, 9, 8, 5, 4, 9, 6. • Extracting these numbers leaves the 11th element as `` and the 12th as `G`. • Sorting the numbers descending (9, 9, 8, 6, 5, 4, 4) and placing them between `` and `G`: `& % β @ # F A L K 9 9 8 6 5 4 4 G @ B S @ € D L K A S ¥ & 8 J B M P W`: Step IV: First ten elements move to the right end. • First 10 elements: `& % β @ # F A L K`: • Moving them to the extreme right gives the final arrangement: ` 9 9 8 6 5 4 4 G @ B S @ € D L K A S ¥ & 8 J B M P W & % β @ # F A L K`: Finding the Answer: • We need to count the elements between the two 'A's in this final sequence. • Position of the first `A`: 18th from the left. • Position of the second `A`: 35th from the left. • Total elements between them = 35 - 18 - 1 = 16. Exam Strategy & Shortcut: Instead of rewriting the entire sequence from scratch for every step, practice "crossing out and re-indexing" elements if allowed on your scratchpad. Since multiple questions rely on the exact final string, perfectly generating the Step IV string once ensures absolute accuracy for all sub-questions. Common Pitfall: The most common mistake occurs in Step II by missing that the first `B` is followed by `S` (a letter) and incorrectly moving it. Always read the character immediately following the target letter carefully! Final Answer: Therefore, the correct answer is 16.

Question 10

Directions: Read the following arrangement of symbols, letters, and numbers carefully and answer the questions based on it.  & F A # L K 4 $ 9 G P @ 8 B S M @ € 5 D % L β K 4 A 9 @ S W ¥ 6 B & 8 # J  Step I: All the symbols, which are immediately fo…

Accepted Answer

Concept & Strategy: For questions asking to locate an element relative to another element's position, always compute the mathematical offset first to save time and reduce counting errors. If both directions are from the same end (e.g., "left of the ... from the left end"), subtract the values. Step-by-Step Solution: First, we must determine the final arrangement by following all four steps meticulously. Initial Arrangement: & F A L K 4 9 G P @ 8 B S M @ € 5 D % L β K 4 A 9 @ S W ¥ 6 B & 8 # J: Step I: Symbols followed by a letter move left. • Moving `&`, `#`, `%`, `β`, `@`, and `#` to the extreme left gives: `& % β @ # F A L K 4 9 G P @ 8 B S M @ € 5 D L K 4 A 9 S W ¥ 6 B & 8 J`: Step II: Letters followed by a symbol move right in alphabetical order. • Moving `P`, `M`, `W`, `B` to the extreme right as B, M, P, W gives: `& % β @ # F A L K 4 9 G @ 8 S @ € 5 D L K 4 A 9 S ¥ 6 & 8 J B M P W`: Step III: Specific numbers move between the 11th and 12th elements. • Extracting 4, 9, 8, 5, 4, 9, 6 (which are between the 7th left and 7th right elements) leaves `` as the 11th and `G` as the 12th. • Sorting descending and placing between `` and `G` gives: `& % β @ # F A L K 9 9 8 6 5 4 4 G @ B S @ € D L K A S ¥ & 8 J B M P W`: Step IV: First ten elements move to the right end. • Moving `& % β @ # F A L K` to the right end gives our final sequence:: ` 9 9 8 6 5 4 4 G @ B S @ € D L K A S ¥ & 8 J B M P W & % β @ # F A L K`: Finding the Target Element: • The question asks for the element 7 to the left of the 21st element from the left end. • Mathematically simplify the position: 21 - 7 = 14th element from the left end. • Counting 14 elements from the left in our final sequence: 1:``, 2:`9`, 3:`9`, 4:`8`, 5:`6`, 6:`5`, 7:`4`, 8:`4`, 9:`G`, 10:`@`, 11:`B`, 12:`S`, 13:`@`, 14:`€`. Exam Strategy & Shortcut: When asked for an element "X to the left of Y from the left end", always perform the arithmetic first. By doing 21 - 7 = 14, you only need to count from the left end once, saving precious time and preventing miscounts during backtracking. Common Pitfall: A frequent error is recounting the elements incorrectly by accidentally skipping symbols like `@` or `€` when scanning the text quickly. Touch or point to each element as you count to exactly 14. Final Answer: Therefore, the correct answer is €.

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