$$\sqrt{\frac{25}{81} - \frac{1}{9}} = x$$
Aptitude
Square Root and Cube Root
Difficulty: Easy
Choose an option
-
A2/3
-
B4/9
-
C16/81
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D25/81
Answer
Correct Answer: 4/9
Explanation
### Concept & Formula
To simplify an expression under a square root involving fractions, find a common denominator to subtract the fractions first, then take the square root of the resulting fraction.
$$\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}$$
### Step-by-Step Solution
* **Given:** The expression $$\sqrt{\frac{25}{81} - \frac{1}{9}}$$
* **Calculation:** Find the common denominator for $81$ and $9$, which is $81$.
Multiply the numerator and denominator of $\frac{1}{9}$ by $9$:
$$\frac{1}{9} = \frac{9}{81}$$
Subtract the fractions inside the radical:
$$\frac{25}{81} - \frac{9}{81} = \frac{16}{81}$$
Take the square root:
$$\sqrt{\frac{16}{81}} = \frac{\sqrt{16}}{\sqrt{81}} = \frac{4}{9}$$
### Exam Strategy & Shortcut
Recognize perfect squares immediately. The numbers $25, 81, 9, 16$ are all perfect squares. As soon as you compute the numerator subtraction $25 - 9 = 16$, you know the answer must be $\sqrt{\frac{16}{81}} = \frac{4}{9}$ without writing down intermediate steps.
### Common Pitfall
* **Mistake:** Distributing the square root over subtraction, i.e., mistakenly computing $\sqrt{\frac{25}{81}} - \sqrt{\frac{1}{9}} = \frac{5}{9} - \frac{1}{3} = \frac{2}{9}$.
* **Correction:** Remember that $\sqrt{A - B} \neq \sqrt{A} - \sqrt{B}$. Always perform the subtraction inside the radical first.
### Final Answer
**Therefore, the correct answer is 4/9.**