The value of $\left( \frac{9^2 \times 18^4}{3^{16}} \right)$ is
Aptitude
Surds and Indices
Difficulty: Hard
Choose an option
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A$\frac{3}{2}$
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B$\frac{4}{9}$
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C$\frac{16}{81}$
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D$\frac{32}{243}$
Answer
Correct Answer: $\frac{16}{81}$
Explanation
## Concept & Formula
This problem requires decomposing composite bases into their prime factors to simplify a complex fractional exponential expression. The primary index laws used are:
$$(a \times b)^n = a^n \times b^n$$
$$(a^m)^n = a^{m \times n}$$
$$\frac{a^m}{a^n} = a^{m - n}$$
## Step-by-Step Solution
* **Given:** The expression to evaluate is $\frac{9^2 \times 18^4}{3^{16}}$.
* **Calculation / Deduction:**
* Step 1: Prime factorize all the bases in the numerator.
* $9 = 3^2$
* $18 = 2 \times 9 = 2 \times 3^2$
* Step 2: Substitute these prime factorizations back into the expression.
$$\frac{(3^2)^2 \times (2 \times 3^2)^4}{3^{16}}$$
* Step 3: Apply the power rules to remove the brackets.
* $(3^2)^2 = 3^4$
* $(2 \times 3^2)^4 = 2^4 \times (3^2)^4 = 2^4 \times 3^8$
* The numerator becomes: $3^4 \times 2^4 \times 3^8$
* Step 4: Combine the terms with the same base in the numerator.
* $2^4 \times (3^4 \times 3^8) = 2^4 \times 3^{12}$
* Step 5: Substitute the simplified numerator back over the denominator.
$$\frac{2^4 \times 3^{12}}{3^{16}}$$
* Step 6: Apply the division rule of indices for base $3$.
$$2^4 \times 3^{12 - 16} = 2^4 \times 3^{-4}$$
* Step 7: Convert the negative exponent into a fraction and evaluate.
$$\frac{2^4}{3^4} = \frac{16}{81}$$
## Exam Strategy & Shortcut
Break numbers down to prime bases immediately. Once you see $9$ and $18$, you know the entire expression consists of base $2$ and base $3$. Tally the powers of $3$ in the numerator mentally: $4$ (from $9^2$) + $8$ (from $18^4$) = $12$. Tally powers of $3$ in denominator: $16$. Net power of $3$ is $-4$ (meaning $3^4$ or $81$ is in the denominator). Tally powers of $2$ in numerator: $4$ (from $18^4$). Numerator is $2^4 = 16$. The answer is $\frac{16}{81}$.
## Common Pitfall
A standard error is miscalculating the expansion of $(2 \times 3^2)^4$. Some students forget to distribute the power of $4$ to the $2$, resulting in an incorrect factor of $2$ instead of $16$. Always distribute the outer exponent to every single factor inside the parenthesis.
## Final Answer
**Therefore, the correct answer is \frac{16}{81}.**