$$ \left(\frac{1}{216}\right)^{-\frac{2}{3}} \div \left(\frac{1}{27}\right)^{-\frac{4}{3}} = $$ $x$
Aptitude
Surds and Indices
Difficulty: Medium
Choose an option
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A$$ \frac{3}{4} $$
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B$$ \frac{2}{3} $$
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C$$ \frac{4}{9} $$
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D$$ \frac{1}{8} $$
Answer
Correct Answer: $$ \frac{4}{9} $$
Explanation
Concept & Formula
This problem tests the inversion rule for negative exponents applied to fractions, followed by exponent simplification.
$$ \left(\frac{a}{b}\right)^{-n} = \left(\frac{b}{a}\right)^n $$
$$ (x^a)^b = x^{ab} $$
Step-by-Step Solution
* First, eliminate the negative signs in the exponents by reciprocating the inner fractions:
$$ \left(\frac{1}{216}\right)^{-\frac{2}{3}} = (216)^{\frac{2}{3}} $$
$$ \left(\frac{1}{27}\right)^{-\frac{4}{3}} = (27)^{\frac{4}{3}} $$
* Convert the bases into their prime power equivalents. $$ 216 = 6^3 $$ and $$ 27 = 3^3 $$.
* Apply the power of a power rule:
$$ (6^3)^{\frac{2}{3}} = 6^2 = 36 $$
$$ (3^3)^{\frac{4}{3}} = 3^4 = 81 $$
* Substitute these simplified values back into the original division operation:
$$ 36 \div 81 = \frac{36}{81} $$
* Simplify the fraction by dividing the numerator and denominator by their greatest common divisor (9):
$$ \frac{36 \div 9}{81 \div 9} = \frac{4}{9} $$
Exam Strategy & Shortcut
Flip the fractions immediately to remove negative powers. Recognize that $$ 216 $$ and $$ 27 $$ are cubes. The denominator 3 in the fractional exponents signals that taking the cube root is your first step. Cube root of 216 is 6; square it to get 36. Cube root of 27 is 3; raise it to the 4th power to get 81. The ratio $$ 36/81 $$ visually reduces to $$ 4/9 $$ quickly using the 9 times table.
Common Pitfall
A major trap is attempting to perform the division operation before simplifying the individual exponential terms. This leads to convoluted algebraic expressions like $$ (1/216 \div 1/27) $$, which jumbles the differing exponents and nearly guarantees a calculation error. Always simplify bases independently first.
Final Answer
**Therefore, the correct answer is $$ \frac{4}{9} $$.**