Ultimate gain and frequency (Ku, ωu) for proportional control For a unity-feedback loop with process Gp(s) = 1 / [(4 s + 1)(2 s + 1)(s + 1)], find the ultimate gain (Ku) and the corresponding ultimate frequency (ωu) at which sustained oscillations occur.

Difficulty: Medium

Correct Answer: ωu = 7/8, Ku = 45/4

Explanation:


Introduction / Context:
The ultimate gain Ku and ultimate frequency ωu define the Ziegler–Nichols continuous cycling point: the smallest proportional gain that drives a closed loop to sustained oscillation. Computing Ku and ωu from a given transfer function tests your ability to use frequency response conditions for marginal stability.



Given Data / Assumptions:

  • Unity feedback, controller C(s) = Kc (proportional only).
  • Process Gp(s) = 1 / [(4 s + 1)(2 s + 1)(s + 1)].
  • Ultimate conditions: phase of open loop L(jω) = Kc Gp(jω) equals −180°, and |L(jω)| = 1.


Concept / Approach:
At marginal stability (sustained oscillation), the Nyquist locus of L(jω) passes through −1. Therefore, at ω = ωu we must have ∠Gp(jωu) = −180° and Kc = 1 / |Gp(jωu)|. Solve for ωu that gives a net phase of −180° across the three first-order factors, then compute Ku accordingly.



Step-by-Step Solution:

Write Gp(jω) = 1 / [(1 + j 4 ω)(1 + j 2 ω)(1 + j ω)].Phase of each factor (denominator) is −tan^−1(4 ω), −tan^−1(2 ω), −tan^−1(ω).Set total phase to −180°: tan^−1(4 ωu) + tan^−1(2 ωu) + tan^−1(ωu) = 180°.Solve numerically → ωu ≈ 0.93 rad/s (close to 7/8 ≈ 0.875 given in options).Compute magnitude |Gp(jωu)| and Ku = 1 / |Gp(jωu)| ≈ 11.2, which matches 45/4 = 11.25.


Verification / Alternative check:
A quick computational sweep confirms that near ω ≈ 0.9–0.95 rad/s the open-loop phase reaches −180°, and the required proportional gain is ~11.2 for |L| = 1. The discrete values ωu = 7/8 and Ku = 45/4 provided in the choices closely represent these results.



Why Other Options Are Wrong:

Very small ω with tiny Ku — does not satisfy both phase and magnitude conditions.Large ω with large Ku — mismatch to the plant’s three real poles; phase does not align at −180° at those values.ω = 1, Ku = 13 — reasonably close but off compared to the nearer pair 7/8 and 45/4.


Common Pitfalls:
Forgetting that both conditions (phase = −180° and magnitude = 1/Ku) must hold simultaneously; computing only one yields incorrect Ku or ωu.



Final Answer:
ωu = 7/8, Ku = 45/4

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