Frequency-domain stability language In loop-shaping and Bode analysis, the phase margin (PM) at the gain crossover frequency is equal to which expression?
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A180° - phase lag
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BPhase lag - 180°
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CPhase lag + 180°
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DPhase lag + 90°
Answer
Correct Answer: 180° - phase lag
Explanation
Introduction / Context:Phase margin is a key robustness metric for single-loop feedback systems. It quantifies how far the loop phase is from the critical −180° at the frequency where the open-loop gain is unity (0 dB). Knowing the correct definition ensures consistent controller tuning and interpretation of Bode plots.
Given Data / Assumptions:
- Open-loop L(jω) = G(jω)H(jω) is stable and minimum-phase for standard definitions.
- Gain crossover frequency ω_gc is where |L(jω_gc)| = 1.
- Phase lag is measured as a positive number representing |∠L(jω)| below 0°.
Concept / Approach:By convention, PM = 180° + ∠L(jω_gc). If we express ∠L(jω_gc) as −(phase lag), then PM = 180° − (phase lag). For example, if the loop phase at crossover is −150°, the phase lag is 150°, and the phase margin is 30°. A positive PM indicates that additional phase lag (e.g., from delays) can be tolerated before instability occurs.
Step-by-Step Solution:
Find ω_gc where |L(jω)| = 1.Read phase ∠L(jω_gc) (a negative value).Compute PM = 180° + ∠L(jω_gc) = 180° − phase lag.Verification / Alternative check:Nyquist interpretation gives the same result: PM is the angle by which the Nyquist curve at |L| = 1 falls short of the −1 point direction.
Why Other Options Are Wrong:
- Phase lag − 180° / +180° / +90°: Do not match the standard definition; they would yield incorrect margins.
Common Pitfalls:Confusing sign conventions or reading the phase at the wrong frequency (ensure it is at gain crossover, not phase crossover).
Final Answer:180° - phase lag