Difficulty: Medium
Correct Answer: 195.66 kN
Explanation:
Introduction / Context:In tension, a riveted (or bolted) plate connection fails on the weakest net section. For zig-zag riveting, the net width is increased by a stagger correction. This problem checks the correct evaluation of net section and allowable tensile capacity using working stress design.
Given Data / Assumptions:
Concept / Approach:
For a zig-zag path cutting two holes on alternate rows, net width = b − n * d0 + Σ(p^2 / (4 * g)) for each staggered pair crossed. Here, n = 2 holes and there is one stagger term because the critical section passes diagonally through adjacent rows.
Step-by-Step Solution:
1) Net width = 150 − 2 * 21.5 + (75^2) / (4 * 60).2) Compute stagger term: 75^2 / (240) = 5625 / 240 = 23.4375 mm.3) Net width = 150 − 43 + 23.4375 = 130.4375 mm.4) Net area A_n = 130.4375 * 10 = 1304.375 mm2.5) Allowable tension = σ_allow * A_n = 150 * 1304.375 = 195,656 N ≈ 195.66 kN.Verification / Alternative check:
Any section cutting three holes (without adequate stagger terms) gives a lower net width due to excessive deductions and is typically not the governing path here with the given layout.
Why Other Options Are Wrong:
195.00 and 192.75 kN round off or under-estimate due to ignoring the stagger correction or rounding area too early; 225.00 kN exceeds the allowable capacity for the given dimensions and stress.
Common Pitfalls:
Using nominal rivet diameter instead of hole diameter for deductions, or forgetting the stagger addition p^2/(4g).
Final Answer:
195.66 kN
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