Reversing digits increases value by 45: When the digits of a two-digit number are interchanged, the resulting number is greater than the original by 45. If the difference between the digits is 5, what is the original number?

Difficulty: Easy

Correct Answer: Cannot be determined

Explanation:


Introduction / Context:
This question tests modeling two-digit numbers and understanding what information is sufficient to determine a unique answer. We will translate the statements into equations and examine whether a single solution or multiple solutions exist.


Given Data / Assumptions:

  • Original number has tens digit a and units digit b.
  • Reversed number is 10b + a and is larger than original by 45.
  • The difference between the digits is 5.


Concept / Approach:
Form two relations: 10b + a = (10a + b) + 45 and |a − b| = 5. Because the reversed number is larger, b > a, hence b − a = 5. We will see that several valid (a, b) pairs satisfy both relations, leading to multiple original numbers.


Step-by-Step Solution:

10b + a = 10a + b + 45 ⇒ 9(b − a) = 45 ⇒ b − a = 5This is identical to the stated digit difference, so both conditions reduce to b − a = 5.Valid pairs with a ≥ 1 (tens digit cannot be 0): (1,6), (2,7), (3,8), (4,9)Corresponding originals: 16, 27, 38, 49


Verification / Alternative check:
For each, reversing increases value by 45 (e.g., 61 − 16 = 45; 72 − 27 = 45, etc.). Thus multiple answers exist.


Why Other Options Are Wrong:

  • 16, 27, 38, 49: Each is possible, but the question asks for a unique original number.


Common Pitfalls:
Assuming uniqueness without checking the digit constraints. Always ensure the system of equations yields a single solution before selecting a numeric option.


Final Answer:
Cannot be determined

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