Equal-split bill with one shortfall: Eleven friends share a hotel bill equally. Ten paid ₹60 each; the 11th paid ₹50 more than his equal share to settle the bill. How much did he pay?

Difficulty: Easy

Correct Answer: ₹115

Explanation:


Introduction / Context:
Bill-splitting questions hinge on identifying the equal share and then incorporating stated deviations (someone paying extra) to balance to the total. Here, the last friend covers not just his share but also a shortfall caused by others paying less than their equal shares.


Given Data / Assumptions:

  • Total bill = 11 * (equal share s).
  • Ten friends each paid ₹60.
  • Eleventh paid (s + ₹50).


Concept / Approach:
Express the total paid both as 11s and as the sum of individual payments, then equate to solve for s. Finally, compute the 11th friend’s payment s + 50.


Step-by-Step Solution:

Total by sum = 10*60 + (s + 50) = 600 + s + 50 = 650 + sBut total must also equal 11s.11s = 650 + s ⇒ 10s = 650 ⇒ s = 65Amount paid by 11th = s + 50 = 65 + 50 = ₹115


Verification / Alternative check:
Compute total: 10*60 + 115 = 600 + 115 = 715. Equal-share total: 11*65 = 715. Both match.


Why Other Options Are Wrong:

  • ₹105, ₹110, ₹120, ₹125: Do not satisfy the equality 11s = 650 + s.


Common Pitfalls:
Assuming the 11th paid ₹110 by adding ₹50 to ₹60; however his equal share is ₹65, so he pays ₹115.


Final Answer:
₹115

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