In digital I/O terminology, when a gate output is at logic HIGH and can deliver current to an external load, this capability is referred to as the output's source current. Assess this definition.
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ACorrect
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BIncorrect
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COnly true for open-collector outputs
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DApplies only to CMOS outputs
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EValid only at 12 V logic levels
Answer
Correct Answer: Correct
Explanation
Introduction / Context:Digital outputs are characterized by how much current they can source (provide) at a HIGH level and sink (absorb) at a LOW level. Knowing the correct terms matters for interfacing logic devices and sizing pull-ups, LEDs, and other loads.
Given Data / Assumptions:
- The statement defines source current for a HIGH output.
- Standard TTL and CMOS push–pull outputs provide both sourcing and sinking capability within specified limits.
- We are not discussing specialized outputs like open-collector (which cannot source in the active sense).
Concept / Approach:“Source current” means current flowing out of the output pin into a load when the pin is at logic HIGH. Conversely, “sink current” is current flowing into the output pin from a load tied to Vcc when the pin is at logic LOW. Datasheets specify I_OH (source) and I_OL (sink) with corresponding guaranteed output voltages (V_OH, V_OL).
Step-by-Step Solution:Check the definition: HIGH output delivering current → source current.Confirm against I/O conventions used in TTL/CMOS datasheets.Conclude the statement aligns with standard usage.
Verification / Alternative check:Typical TTL specs: I_OH is smaller than I_OL, reflecting stronger sink capability; nonetheless, I_OH is the rated source current at logic HIGH.
Why Other Options Are Wrong:Limiting it to open-collector or CMOS is inaccurate; the term is technology-agnostic. Logic level 12 V is unrelated to TTL/CMOS standard levels.
Common Pitfalls:Confusing current direction; some beginners think “source” applies to LOW. Remember: source at HIGH, sink at LOW for push–pull drivers.
Final Answer:Correct