Reflected resistance: A transformer has a 1:6 turns ratio (Np:Ns = 1:6) and a 470 Ω load on the secondary. What is the equivalent load resistance seen at the primary?

Difficulty: Easy

Correct Answer: 13 Ω

Explanation:


Introduction / Context:
Transformers reflect impedances by the square of the turns ratio. This principle is pivotal in matching sources to loads, optimizing power transfer, and designing audio/RF interfaces.


Given Data / Assumptions:

  • Turns ratio Np:Ns = 1:6.
  • Secondary (load-side) resistance RL = 470 Ω.
  • Ideal transformer approximation.


Concept / Approach:
Reflected (equivalent) resistance at the primary is R_in = (Np/Ns)^2 * RL. Because Np < Ns, the resistance seen at the primary will be much smaller than RL (step-down of resistance by the squared ratio).


Step-by-Step Solution:

Compute the square of the turns ratio: (Np/Ns)^2 = (1/6)^2 = 1/36.R_in = (1/36) * 470 Ω ≈ 13.0556 Ω.Rounded to the nearest whole ohm, R_in ≈ 13 Ω.


Verification / Alternative check:
As a quick check, 36 * 13 Ω ≈ 468 Ω, close to the actual 470 Ω, confirming the arithmetic.


Why Other Options Are Wrong:

  • 78 Ω or 7.8 Ω or 1.3 Ω: These correspond to using the wrong ratio or misplacing the decimal.
  • 28 Ω: Not consistent with the required 1/36 factor.


Common Pitfalls:

  • Using Ns/Np instead of Np/Ns in the square.
  • Forgetting to square the turns ratio when reflecting resistance.


Final Answer:
13 Ω

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion