DC on transformers again: A 6 V battery is connected across the primary of a transformer with turns ratio 8 (Np/Ns or 8:1). What steady-state secondary voltage results?
-
A0 V
-
B6 V
-
C48 V
-
D0.75 V
-
E24 V
Answer
Correct Answer: 0 V
Explanation
Introduction / Context:Transformers need time-varying magnetic fields to induce a secondary voltage. A DC battery, after a brief switching transient, produces no sustained change in flux, so no sustained induced secondary voltage appears. This question reinforces that concept.
Given Data / Assumptions:
- Primary excitation is DC: 6 V battery.
- Turns ratio magnitude 8 (step-down or step-up irrelevant for DC steady state).
- Steady-state condition after initial connection transient.
Concept / Approach:Induced EMF magnitude is proportional to dΦ/dt. With DC, dΦ/dt → 0 as current stabilizes; therefore, Vs → 0 V in steady state. (Practical note: continuous DC can overheat the primary and saturate the core; this is outside the scope of the numeric answer.)
Step-by-Step Solution:
Apply DC → only a momentary change in flux during switch-on.After settling, flux is constant → induced voltage is zero.Secondary steady-state voltage = 0 V.Verification / Alternative check:An oscilloscope would show a spike at connection then decay to zero volts on the secondary, confirming the reasoning.
Why Other Options Are Wrong:
- 6 V, 48 V, 0.75 V: These apply AC ratio logic to DC, which is invalid at steady state.
- 24 V: Also misapplies the turns relation to DC.
Common Pitfalls:
- Using the turns ratio directly on DC values.
- Ignoring transient versus steady-state distinction.
Final Answer:0 V