A train 160 m long passes a standing man in 18 seconds. What is the speed of the train (in km/h)?

Introduction / Context:Crossing a stationary observer requires the train to travel a distance equal to its length. We compute speed from distance and time, then convert to km/h for the final answer.

Given Data / Assumptions:

• L = 160 m.
• t = 18 s.

Concept / Approach:Speed in m/s = distance / time = 160 / 18 = 8.888... m/s. Convert to km/h by multiplying by 3.6.

Step-by-Step Solution:v = 160 / 18 ≈ 8.888... m/s.In km/h: 8.888... * 3.6 ≈ 32 km/h.

Verification / Alternative check:At 32 km/h (8.888... m/s), 18 s covers 160 m, matching the data.

Why Other Options Are Wrong:28 or 36 km/h would yield lengths different from 160 m in 18 s.

Common Pitfalls:Forgetting to convert m/s to km/h correctly or rounding too early.

Final Answer:32 km/h