Train crossing a platform – computing time A train 280 m long moves at 60 km/h. How many seconds are required to cross a platform 220 m long?

Difficulty: Easy

Correct Answer: 30 sec

Explanation:


Introduction / Context:
This is a direct application of distance = speed * time, with total distance equal to train length plus platform length and careful unit conversion from km/h to m/s.


Given Data / Assumptions:

  • Train length = 280 m.
  • Platform length = 220 m.
  • Speed = 60 km/h.


Concept / Approach:
Convert speed and compute time using total distance.


Step-by-Step Solution:

v = 60 * 1000 / 3600 = 16.666... m/sD = 280 + 220 = 500 mt = 500 / (60 * 1000 / 3600) = 500 / 16.666... = 30 s


Verification / Alternative check:
16.666... m/s * 30 s = 500 m, which equals the combined lengths.


Why Other Options Are Wrong:
20 s, 25 s, 35 s: Each gives the wrong travel distance at the given speed. Only 30 s is exact.


Common Pitfalls:
Forgetting to add both lengths or rounding 16.666... too early. Keep exact fraction 50/3 when possible.


Final Answer:
30 sec

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