Directions : Study the following table carefully and answer the questions that follow: (Bank P.O., 2011) Semester Fees (In ₹ thousands) For Five Different Courses In 6 Different Years | Years | B.Tech | M.Sc. | B.Ed. | M.Phil | Diploma | |---|---|---|---|---|---| | 2005 | 11.5 | 5.8 | 7.5 | 4.7 | 1.8 | | 2006 | 14.5 | 6.4 | 11.6 | 5.8 | 3.2 | | 2007 | 20.0 | 10.2 | 13.9 | 8.6 | 4.8 | | 2008 | 22.2 | 14.6 | 15.8 | 12.7 | 5.6 | | 2009 | 35.8 | 17.7 | 18.5 | 25.1 | 12.5 | | 2010 | 50.7 | 20.9 | 22.6 | 18.9 | 14.9 | What was the total semester fee charged for all the courses together in the year 2006 ?

### Concept & Basic Arithmetic To find the total across all categories for a specific year, sum all the values in the row corresponding to that year. Ensure the final result is scaled correctly according to the table's unit (₹ thousands). ### Step-by-Step Solution 1. **Locate Row:** Find the row for the year 2006. 2. **Extract Data:** The fees for B.Tech, M.Sc., B.Ed., M.Phil, and Diploma are $14.5, 6.4, 11.6, 5.8,$ and $3.2$ respectively. 3. **Calculate Sum:** $$ 14.5 + 6.4 + 11.6 + 5.8 + 3.2 = 41.5 $$ 4. **Convert to Actual Currency:** Multiply by $1000$. $$ 41.5 \times 1000 = 41500 $$ ### Exam Strategy & Shortcut Sum the decimals (tenths place) first to determine the final digit: $.5 + .4 + .6 + .8 + .2 = 2.5$. This means the total sum ends in $.5$. The only options that translate to a $.5$ in the thousands position ($41.5$ or $42.5$) are 41500 and 42500. Then quickly sum the integers: $14+6+11+5+3 = 39$. Add the $2.5$ carried over: $39 + 2.5 = 41.5$. Thus, 41500 is correct. ### Common Pitfall A common mistake in horizontal addition is skipping a column or accidentally taking a number from the row above or below. Using a straight edge or running a finger across the exact row helps prevent this. ### Final Answer Therefore, the correct answer is **₹ 41500**.