Directions : Study the following table carefully and answer the questions that follow: (Bank P.O., 2011) Semester Fees (In ₹ thousands) For Five Different Courses In 6 Different Years | Years | B.Tech | M.Sc. | B.Ed. | M.Phil | Diploma | |---|---|---|---|---|---| | 2005 | 11.5 | 5.8 | 7.5 | 4.7 | 1.8 | | 2006 | 14.5 | 6.4 | 11.6 | 5.8 | 3.2 | | 2007 | 20.0 | 10.2 | 13.9 | 8.6 | 4.8 | | 2008 | 22.2 | 14.6 | 15.8 | 12.7 | 5.6 | | 2009 | 35.8 | 17.7 | 18.5 | 25.1 | 12.5 | | 2010 | 50.7 | 20.9 | 22.6 | 18.9 | 14.9 | What was the difference between the total semester fee charged for Diploma course over the years together and the fee charged for B.Tech Course in the year 2009 ?

### Concept & Basic Arithmetic This question requires summing a column of data, identifying a single specific data point, and finding their absolute difference. The final result must be scaled by the unit multiplier (thousands). ### Step-by-Step Solution 1. **Calculate Diploma Total:** Sum all values in the Diploma column. $$ 1.8 + 3.2 + 4.8 + 5.6 + 12.5 + 14.9 = 42.8 $$ 2. **Identify B.Tech 2009 Fee:** Look up the value for B.Tech in the year 2009. $$ \text{Value} = 35.8 $$ 3. **Calculate Difference:** Subtract the B.Tech fee from the Diploma total. $$ 42.8 - 35.8 = 7.0 $$ 4. **Convert to Actual Currency:** Multiply by $1000$. $$ 7.0 \times 1000 = 7000 $$ ### Exam Strategy & Shortcut Instead of summing all Diploma fees completely and then subtracting, you can keep a running tally and subtract $35.8$ at the end, or look at the unit digits. $8+2+8+6+5+9 = 38$ (ends in $.8$). $35.8$ also ends in $.8$. Therefore, the difference must end in $.0$. The integer difference is $42 - 35 = 7$. $7.0 \times 1000 = 7000$. ### Common Pitfall Misreading the table by summing the B.Tech column instead of pulling the single 2009 value, or vice versa for the Diploma column. Always read multi-part conditions carefully. ### Final Answer Therefore, the correct answer is **₹ 7000**.