Difficulty: Easy
Correct Answer: Maximum at the inner surface and zero at the outer surface (when no external pressure)
Explanation:
Introduction / Context:Design of thick-walled pressure components requires correct understanding of radial and hoop stress distributions. Errors in the sign or boundary conditions can seriously compromise safety.
Given Data / Assumptions:
Concept / Approach:From Lame’s equations: sigma_r = A − B/r^2. Boundary conditions for internal-only pressure are sigma_r(r_i) = −p (compressive) and sigma_r(r_o) = 0. Thus the largest magnitude of radial stress occurs at the inner radius and decreases to zero at the outer radius.
Step-by-Step Solution:
Apply inner boundary: sigma_r(r_i) = −p (maximum compressive).Apply outer boundary: sigma_r(r_o) = 0 (free surface).Therefore, radial stress varies from −p at r_i to 0 at r_o; it is not uniform.Verification / Alternative check:Plotting sigma_r versus r yields a monotonic curve increasing from −p to 0. Hoop stress sigma_theta remains tensile and larger than |sigma_r| near the inner radius.
Why Other Options Are Wrong:Options (a) and (c) reverse the boundary conditions.Option (b) is incomplete; it omits that sigma_r at the outer surface equals zero when external pressure is absent.Uniform distribution is a thin-wall assumption for hoop stress, not for radial stress in thick walls.
Common Pitfalls:Assuming thin-wall results; forgetting that radial stress at a free outer surface is zero when no external pressure acts.
Final Answer:
Maximum at the inner surface and zero at the outer surface (when no external pressure)
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