Field distribution in TE10 mode — location of maximum E-field For the dominant TE10 mode in a rectangular waveguide, where does the electric field have its maximum magnitude?

Introduction / Context:Knowing where fields peak inside a waveguide is critical for breakdown assessment, probe placement, and coupling design. In TE10, the dominant transverse electric field varies sinusoidally across the broad wall dimension.

Given Data / Assumptions:

• Rectangular waveguide with width a (broad wall) and height b (narrow wall).
• Mode: TE10 (m = 1, n = 0).

Concept / Approach:The principal field component varies as a cosine function across the a-dimension and is uniform across b. Boundary conditions enforce zero tangential electric field at the conducting walls (x = 0 and x = a), with a maximum at the midpoint x = a/2. Thus, the electric field maximum lies along the center line of the broad wall.

Step-by-Step Solution:

Verification / Alternative check:Standard field plots and coupling-probe placements show strongest coupling at x = a/2 for TE10, confirming the location of the E-field maximum.

Why Other Options Are Wrong:

• B: The field is zero at the side walls, not maximum.
• C/D: Contradict the sinusoidal distribution and boundary conditions.

Common Pitfalls:Confusing TE10 with higher-order modes; misapplying boundary conditions at conductor walls.

Final Answer:along centre line of broad wall (i.e. x = a/2)