Circular waveguides and symmetry: Which modes exhibit circular symmetry (no azimuthal variation, i.e., m = 0)?
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ATE11
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BTE11 and TE21
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CTE01
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DTE01 and TM01
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ETM11 only
Answer
Correct Answer: TE01 and TM01
Explanation
Introduction:Modes in circular waveguides are labeled TEmn or TMmn, where m is the azimuthal index and n is the radial index. Circular symmetry means the fields do not depend on the azimuthal angle φ; this property is pivotal in certain low-loss transmission applications and in mode converters.
Given Data / Assumptions:
- Circular, air-filled, perfectly conducting waveguide.
- Mode labeling follows standard conventions.
- Circular symmetry corresponds to m = 0.
Concept / Approach:
For circular symmetry, m must be zero, so any TE0n and TM0n mode qualifies. The options that meet this requirement are TE01 and TM01 together. Modes with m ≥ 1 (e.g., TE11, TM11, TE21) vary with φ and are not circularly symmetric.
Step-by-Step Solution:
Identify symmetry condition: m = 0 → no φ dependence.Find modes: TE01 (m = 0, n = 1) and TM01 (m = 0, n = 1) satisfy the condition.Exclude modes with m ≥ 1: TE11, TM11, TE21 are not symmetric.Verification / Alternative check:
Field plots for TE01/TM01 show concentric circles with purely radial variation; no angular lobes appear, confirming circular symmetry and explaining their use in low-loss long-distance waveguide systems (especially TE01 at high power).
Why Other Options Are Wrong:
- TE11 or TE11 and TE21: these have m ≠ 0, so they are not circularly symmetric.
- TE01 alone omits TM01, which is also symmetric.
- TM11 only: m = 1, not symmetric.
Common Pitfalls:
Confusing the dominant mode in circular guides (TE11) with circular symmetry. Dominance relates to lowest cutoff; symmetry relates to angular dependence.
Final Answer:
TE01 and TM01