Free Vortex — Speed–Radius Relationship For a free vortex (no external torque), the tangential velocity of a water particle varies with distance r from the centre as:
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Adirectly proportional to r
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Binversely proportional to r
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Cdirectly proportional to r^2
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Dinversely proportional to r^2
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E—
Answer
Correct Answer: inversely proportional to r
Explanation
Introduction:Vortical motions are classified as free (irrotational, no forced swirl) or forced (solid-body rotation). The velocity–radius law distinguishes them and determines pressure distribution and surface shape.
Given Data / Assumptions:
- Free vortex in incompressible, inviscid approximation.
- No external torque; angular momentum of each fluid particle is conserved.
- Steady, axisymmetric flow.
Concept / Approach:For a free vortex, tangential momentum mv_thetar is constant along a streamline (neglecting viscosity). Therefore v_theta * r = constant ⇒ v_theta ∝ 1/r. The flow is irrotational except at the core.
Step-by-Step Solution:Use angular momentum conservation: v_theta*r = K (constant).Rearrange to get v_theta = K/r.Hence as r increases, v_theta decreases proportionally to 1/r.
Verification / Alternative check:Measured velocities in drain whirlpools and tornado outer regions follow approximately v ∝ 1/r, unlike forced vortices where v ∝ r.
Why Other Options Are Wrong:v ∝ r: describes forced vortex (solid-body) rotation.v ∝ r^2 or v ∝ 1/r^2: do not conserve angular momentum for free vortices.
Common Pitfalls:Confusing free with forced vortex; assuming solid-body rotation where none exists; ignoring viscous core where the ideal relation breaks down.
Final Answer:inversely proportional to r