Critical depth in a rectangular channel in terms of unit discharge q (discharge per unit width): Select the correct expression for y_c.

Difficulty: Medium

Correct Answer: y_c = (q^2 / g)^(1/3)

Explanation:


Introduction / Context:
Critical flow in open channels corresponds to Froude number Fr = 1. For a rectangular channel, the critical depth y_c is directly related to the unit discharge q (discharge per unit width). Correctly recalling this formula is fundamental in flow measurement and control structure design.


Given Data / Assumptions:

  • Rectangular channel of unit width for unit discharge definition
  • Steady, prismatic, frictionless control section
  • Acceleration due to gravity g is constant


Concept / Approach:
For a rectangular channel, specific energy E = y + v^2/(2g). At critical flow, dE/dy = 0 which leads to v_c^2 = g * y_c. Since q = v * y for unit width, combine to obtain y_c in terms of q and g.


Step-by-Step Solution:

At critical: v_c^2 = g * y_cUse q = v_c * y_c ⇒ v_c = q / y_cSubstitute: (q / y_c)^2 = g * y_cRearrange: q^2 = g * y_c^3Solve: y_c = (q^2 / g)^(1/3)


Verification / Alternative check:
Dimensional check: [q] = m^2/s for unit width; q^2/g has dimension m^3; cube root gives meters, consistent for depth.


Why Other Options Are Wrong:

  • (g / q^2)^(1/3): Inverts the relation; would have dimension 1/m, not a length.
  • (q / g)^(1/2): Wrong power and units.
  • q / g: Linear in q, dimension m^2/s^2, not a length.


Common Pitfalls:
Forgetting that q is per unit width; applying the same formula to non-rectangular sections without the appropriate geometric function; mixing up specific energy and specific force criteria.


Final Answer:
y_c = (q^2 / g)^(1/3)

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