Difficulty: Medium
Correct Answer: y_c = (q^2 / g)^(1/3)
Explanation:
Introduction / Context:Critical flow in open channels corresponds to Froude number Fr = 1. For a rectangular channel, the critical depth y_c is directly related to the unit discharge q (discharge per unit width). Correctly recalling this formula is fundamental in flow measurement and control structure design.
Given Data / Assumptions:
Concept / Approach:For a rectangular channel, specific energy E = y + v^2/(2g). At critical flow, dE/dy = 0 which leads to v_c^2 = g * y_c. Since q = v * y for unit width, combine to obtain y_c in terms of q and g.
Step-by-Step Solution:
At critical: v_c^2 = g * y_cUse q = v_c * y_c ⇒ v_c = q / y_cSubstitute: (q / y_c)^2 = g * y_cRearrange: q^2 = g * y_c^3Solve: y_c = (q^2 / g)^(1/3)Verification / Alternative check:Dimensional check: [q] = m^2/s for unit width; q^2/g has dimension m^3; cube root gives meters, consistent for depth.
Why Other Options Are Wrong:
Common Pitfalls:Forgetting that q is per unit width; applying the same formula to non-rectangular sections without the appropriate geometric function; mixing up specific energy and specific force criteria.
Final Answer:y_c = (q^2 / g)^(1/3)
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