Transitive speed comparison — Decide if the final relation is implied Premise 1: Taking the train across town is quicker than taking the bus. Premise 2: Taking the bus across town is slower than driving a car. Claim (to evaluate): Taking the train across town is quicker than driving a car.

Difficulty: Easy

Correct Answer: uncertain

Explanation:


Introduction / Context:
This item tests whether two pairwise comparisons force a third comparison. We compare travel modes by relative speed (quicker means higher speed/less time). We must check whether “train vs. car” is determined from the two given premises.


Given Data / Assumptions:

  • Train quicker than bus.
  • Bus slower than car (equivalently, car quicker than bus).
  • No explicit comparison between train and car is given.
  • Conditions (traffic, routes) are assumed constant within each premise but not across modes unless stated.


Concept / Approach:

  • From A > B and C > B, nothing follows about A vs. C. Either A > C, A = C, or C > A could hold.
  • Therefore, the claim cannot be deduced.


Step-by-Step Solution:

Let speeds be numeric: bus = 10 units.Choose train = 12 (train quicker than bus) and car = 14 (car quicker than bus). Then train quicker than car is false.Alternatively, if car = 11 and train = 15, then the claim is true. Both scenarios satisfy the premises, so the claim is indeterminate.


Verification / Alternative check:

Graphically: both train and car lie to the right of bus on a speed line, but their mutual order is unspecified.


Why Other Options Are Wrong:

true / false: Each can be consistent with the premises; neither is forced.both true and false: A single world cannot have contradictory comparisons; uncertainty reflects multiple possible worlds.


Common Pitfalls:

Assuming transitivity incorrectly from “better than bus” for both modes. Transitivity needs a chain A > B > C to infer A > C, which we do not have here.


Final Answer:

uncertain

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