Synchronous counter behavior: evaluate the statement about clocking “In a synchronous (parallel-clocked) counter, each state transition is driven by the same clock pulse applied to every flip-flop.” Decide whether this statement holds in general practice.

Introduction / Context:
Counters come in two broad classes: asynchronous (ripple) and synchronous (parallel). The difference determines timing accuracy, maximum frequency, and ease of decoding. This question checks whether synchronous counters share a common clock for all internal flip-flops.

Given Data / Assumptions:

• Synchronous counters are designed so that all flip-flops receive the same clock edge simultaneously.
• State transitions are determined by combinational logic feeding the flip-flop inputs.
• Propagation delays exist but are confined to the input logic paths, not a cascaded clock chain.

Concept / Approach:
In a synchronous counter, the defining feature is a common clock network to every stage. The next state is computed by combinational gates, often using enables or carry/borrow signals, but the actual switching of flip-flops occurs together on the same active clock edge. This reduces accumulated timing skew typical of ripple designs.

Step-by-Step Solution:
Identify counter type: synchronous.Check clocking scheme: one shared clock node to all flip-flops.Next-state logic prepares D, T, or J/K inputs prior to the edge.On the clock edge, all stages sample concurrently, producing a uniform state transition.

Verification / Alternative check:
Timing diagrams show simultaneous output updates at each clock edge (within flip-flop clock-to-Q delay), unlike ripple counters where edges propagate stage-by-stage.

Why Other Options Are Wrong:
“Incorrect” contradicts the defining characteristic. “Only true for ripple counters” reverses the truth. “Only true when using T flip-flops” is wrong; the property is independent of flip-flop flavor (D, T, or J-K) as long as they share the clock.

Common Pitfalls:
Confusing carry-enable chains (combinational) with clock chaining; assuming shared clock eliminates all skew (layout still matters).

Final Answer:
Correct