If $4x = p(x + 3) + q(x - 1)$ is an identity, then the values of $p$ and $q$ are
Aptitude
Simplification
Difficulty: Medium
Choose an option
-
A1, -3
-
B1, 3
-
C1, 1
-
D3, 1
Answer
Correct Answer: 1, 3
Explanation
### Concept & Strategy
This question involves a **Polynomial Identity**. An identity means the equation holds true for *any* possible value of $x$.
We can solve this using two main strategies:
1. **Coefficient Equating:** Expand the right side and equate the coefficients of $x$ and the constant terms to the left side.
2. **Strategic Substitution:** Choose clever values for $x$ that make terms cancel out (become zero), allowing instant evaluation of $p$ and $q$. (This is the faster method).
### Step-by-Step Solution (Substitution Method)
Since the equation is an identity, it works for all values of $x$. We pick values that make the brackets zero.
* **Step 1: Solve for p by eliminating q**
To make the $q$ term disappear, we set $x - 1 = 0$, which means $x = 1$. Substitute $x = 1$ into the entire equation:
$$4(1) = p(1 + 3) + q(1 - 1)$$
$$4 = p(4) + 0$$
$$4 = 4p$$
$$p = 1$$
* **Step 2: Solve for q by eliminating p**
To make the $p$ term disappear, we set $x + 3 = 0$, which means $x = -3$. Substitute $x = -3$ into the entire equation:
$$4(-3) = p(-3 + 3) + q(-3 - 1)$$
$$-12 = p(0) + q(-4)$$
$$-12 = -4q$$
$$q = \frac{-12}{-4} = 3$$
### Exam Strategy & Shortcut
The Strategic Substitution method shown above *is* the ultimate exam shortcut for identity problems. It bypasses the need to create and solve simultaneous equations entirely. The moment you see $(x-1)$ and $(x+3)$, you should mentally plug in $x=1$ (yielding $4=4p \rightarrow p=1$) and look at the options. Options (a), (b), and (c) all have $p=1$. Then quickly plug in $x=-3$ (yielding $-12=-4q \rightarrow q=3$). The answer is (b).
### Common Pitfall
Students often default to expanding the expression: $4x = px + 3p + qx - q$, then grouping: $4x = (p+q)x + (3p-q)$. This creates a system of equations: $p+q=4$ and $3p-q=0$. While this method is mathematically sound, it is time-consuming and introduces more opportunities for basic addition/subtraction errors compared to strategic substitution.
### Final Answer
Therefore, the correct answer is **1, 3**.