The sum of the squares of two numbers is 234, and the square of their difference is 144. Find the product of the two numbers.

Difficulty: Easy

Correct Answer: 45

Explanation:


Introduction / Context:
This problem uses algebraic identities that relate sums and differences to products. Specifically, knowing a^2 + b^2 and (a − b)^2 enables solving for ab via identity manipulations without finding a and b individually.


Given Data / Assumptions:

  • a^2 + b^2 = 234.
  • (a − b)^2 = 144.
  • Need ab.


Concept / Approach:
Use the identity (a − b)^2 = a^2 + b^2 − 2ab. Rearranging gives 2ab = (a^2 + b^2) − (a − b)^2. Substitute the given values to compute ab directly.


Step-by-Step Solution:

(a − b)^2 = a^2 + b^2 − 2ab144 = 234 − 2ab2ab = 234 − 144 = 90ab = 90 / 2 = 45


Verification / Alternative check:
If desired, we can choose numbers with product 45 that fit the constraints (not necessary here). The identity-based computation is sufficient and exact.


Why Other Options Are Wrong:

  • 28, 52, 36, 40: These do not satisfy 2ab = 90; substituting back fails the identity relation.


Common Pitfalls:

  • Using (a + b)^2 identity mistakenly instead of (a − b)^2.
  • Sign errors when isolating 2ab.


Final Answer:
45

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