Percent error propagation in area of a square:\nIf the measured side of a square is 2% too large, what is the percentage error in the calculated area?

Difficulty: Easy

Correct Answer: 4.04%

Explanation:


Introduction / Context:
Area of a square varies with the square of its side. A small percentage error in the side propagates roughly twice to area, but exactly it follows the square of the multiplicative factor.


Given Data / Assumptions:

  • Measured side = 1.02 * true side (2% excess).
  • Area scales with side^2.


Concept / Approach:
New area factor = (1.02)^2 = 1.0404 → 4.04% excess in area. Hence the percent error in area is +4.04%.


Step-by-Step Solution:

Let true side = s, true area = s^2.Measured side = 1.02s → computed area = (1.02s)^2 = 1.0404 s^2.Percent error = (1.0404 − 1) * 100% = 4.04%.


Verification / Alternative check:
Linear approximation gives ~2 * 2% = 4%, close to exact 4.04%, validating the calculation.


Why Other Options Are Wrong:
5.04%, 6.04%, 7.04%, 3.96% do not match the exact square of 1.02.


Common Pitfalls:
Doubling the percentage and ignoring the small quadratic term, or subtracting instead of adding when error is in excess.


Final Answer:
4.04%

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