Difficulty: Medium
Correct Answer: decreased with the increase in pressure
Explanation:
Introduction / Context:
Many liquid–liquid and gas–liquid solutions exhibit a non-ideal volume change on mixing. When the total volume of the solution exceeds the sum of the pure-component volumes, the mixture displays a positive excess molar volume. Le Chatelier’s principle and fundamental thermodynamics allow us to predict how pressure affects solubility under such conditions.
Given Data / Assumptions:
Concept / Approach:
For a process that increases volume (positive ΔV_mix > 0), an increase in pressure shifts equilibrium to reduce the total volume. According to dG = V dP − S dT and the pressure derivative of chemical potential, higher pressure penalizes states with larger partial molar volumes. Therefore, pressure opposes the extent of a mixing process that creates additional volume, decreasing the solubility of the solute in the solvent when ΔV_mix is positive.
Step-by-Step Solution:
Verification / Alternative check:
In partial molar terms, μ_i(P) increases with P roughly by ∫ V̄_i dP. A positive excess volume implies larger V̄_i upon mixing; increasing P raises μ_i of the mixed state more than that of unmixed components, reducing the driving force for dissolution and thus lowering solubility.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing this case with gas solubility following Henry’s law (often increases with pressure). Here the key is the sign of excess volume of mixing for the specific solution in question.
Final Answer:
decreased with the increase in pressure
Discussion & Comments