The simple interest at $x$% for $x$ years will be ₹ $x$ on a sum of :
Aptitude
Simple Interest
Difficulty: Easy
Choose an option
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A₹ $x$
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B₹ $\left(\frac{100}{x}\right)$
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C₹ $100x$
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D₹ $\left(\frac{100}{x^2}\right)$
Answer
Correct Answer: ₹ $\left(\frac{100}{x}\right)$
Explanation
### Concept & Algebraic Substitution in Simple Interest
The same standard formula applies even when the values are variables. We isolate the Principal ($P$):
$$P = \frac{SI \times 100}{R \times T}$$
### Step-by-Step Solution
* Given Simple Interest, $SI = x$
* Given Rate, $R = x\%$ p.a.
* Given Time, $T = x \text{ years}$
* Substitute these variable values into the formula:
$P = \frac{x \times 100}{x \times x}$
* Cancel out the common $x$ from the numerator and denominator:
$P = \frac{100}{x}$
### Exam Strategy & Shortcut
Whenever $SI$, $R$, and $T$ are all equal to the same variable $x$, the formula $P = \frac{SI \times 100}{R \times T}$ immediately simplifies to $\frac{100}{x}$ because one $x$ from the numerator ($SI$) cancels out one $x$ from the denominator ($R \times T$).
### Common Pitfall
A common mistake is accidentally multiplying the terms to get $\frac{100}{x^2}$ instead of canceling the $x$ properly.
### Final Answer
Therefore, the correct answer is **₹ $\left(\frac{100}{x}\right)$**.