Stress distribution in simple bending of beams
Under the assumptions of simple (Euler–Bernoulli) bending,
how does normal bending stress vary from the neutral axis to the outer fibers?
Choose the correct variation.
Difficulty: Easy
Correct Answer: linearly
Explanation:
ConceptFrom σ = M y / I, the bending stress is proportional to distance y from the neutral axis. Hence it varies linearly, zero at the NA and maximum at the extreme fibers.
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