Stress distribution in simple bending of beams Under the assumptions of simple (Euler–Bernoulli) bending, how does normal bending stress vary from the neutral axis to the outer fibers? Choose the correct variation.
Mechanical Engineering
Strength of Materials
Difficulty: Easy
Choose an option
-
Alinearly
-
Bparabolically
-
Chyperbolically
-
Delliptically
Answer
Correct Answer: linearly
Explanation
ConceptFrom σ = M y / I, the bending stress is proportional to distance y from the neutral axis. Hence it varies linearly, zero at the NA and maximum at the extreme fibers.
Final Answerlinearly