Definition of shear force at a section of a beam For a simply supported (or any) beam, the shear force at a given cross-section is equal to the:

Mechanical Engineering Strength of Materials Difficulty: Easy
Choose an option
  • A
    Displacement of the neutral axis
  • B
    Sum of all forces on the beam
  • C
    Sum of the transverse forces (without sign) on the beam
  • D
    Algebraic sum of the transverse forces on one side of the section
  • E
    Curvature of the neutral axis

Answer

Correct Answer: Algebraic sum of the transverse forces on one side of the section

Explanation

Introduction / Context:Shear force and bending moment diagrams are constructed from equilibrium of a cut section. A precise definition of shear force at a section is essential before solving for reactions, internal forces, and drawing diagrams.

Given Data / Assumptions:

  • Beam subjected to transverse loading (point loads, UDLs, etc.).
  • Statics: equilibrium of a free-body diagram (FBD) of part of the beam.
  • Sign convention for shear: typically upward on left face positive (or another consistent convention).

Concept / Approach:

At a chosen section, we isolate one part of the beam. The internal shear force V at that section balances the algebraic sum of all external transverse forces on the isolated part. Therefore, V equals the algebraic sum (with sign) of transverse forces acting on either the left or the right segment of the cut, not the entire beam.

Step-by-Step Solution:

Cut the beam at the section of interest.Write ΣF_y = 0 for one side of the cut (left or right).Solve for internal shear V; this is the algebraic sum of transverse forces on that side.

Verification / Alternative check:

Consistency check: Shear force diagram slope equals negative of load intensity (dV/dx = −w), derived from this definition and equilibrium, reinforcing the sign-aware summation concept.

Why Other Options Are Wrong:

  • (a) and (e) are deformation measures, not force definitions.
  • (b) takes forces from both sides and along all directions, which is not how shear is defined at a section.
  • (c) omits algebraic sign, losing directionality necessary for equilibrium.

Common Pitfalls:

  • Summing forces on both sides of the cut, which trivially gives zero and is meaningless for finding internal forces.

Final Answer:

Algebraic sum of the transverse forces on one side of the section.

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