Definition of shear force at a section of a beam For a simply supported (or any) beam, the shear force at a given cross-section is equal to the:
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ADisplacement of the neutral axis
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BSum of all forces on the beam
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CSum of the transverse forces (without sign) on the beam
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DAlgebraic sum of the transverse forces on one side of the section
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ECurvature of the neutral axis
Answer
Correct Answer: Algebraic sum of the transverse forces on one side of the section
Explanation
Introduction / Context:Shear force and bending moment diagrams are constructed from equilibrium of a cut section. A precise definition of shear force at a section is essential before solving for reactions, internal forces, and drawing diagrams.
Given Data / Assumptions:
- Beam subjected to transverse loading (point loads, UDLs, etc.).
- Statics: equilibrium of a free-body diagram (FBD) of part of the beam.
- Sign convention for shear: typically upward on left face positive (or another consistent convention).
Concept / Approach:
At a chosen section, we isolate one part of the beam. The internal shear force V at that section balances the algebraic sum of all external transverse forces on the isolated part. Therefore, V equals the algebraic sum (with sign) of transverse forces acting on either the left or the right segment of the cut, not the entire beam.
Step-by-Step Solution:
Cut the beam at the section of interest.Write ΣF_y = 0 for one side of the cut (left or right).Solve for internal shear V; this is the algebraic sum of transverse forces on that side.Verification / Alternative check:
Consistency check: Shear force diagram slope equals negative of load intensity (dV/dx = −w), derived from this definition and equilibrium, reinforcing the sign-aware summation concept.
Why Other Options Are Wrong:
- (a) and (e) are deformation measures, not force definitions.
- (b) takes forces from both sides and along all directions, which is not how shear is defined at a section.
- (c) omits algebraic sign, losing directionality necessary for equilibrium.
Common Pitfalls:
- Summing forces on both sides of the cut, which trivially gives zero and is meaningless for finding internal forces.
Final Answer:
Algebraic sum of the transverse forces on one side of the section.