Simply supported beam of span L under a uniformly distributed load (total load notation) A simply supported beam of clear span L carries a uniformly distributed load whose total magnitude over the span is W. What is the maximum bending moment M (sagging) in the beam?

Difficulty: Easy

Correct Answer: M = W L / 8

Explanation:


Introduction / Context:
The maximum bending moment for a simply supported beam under a uniformly distributed load (UDL) depends on whether the symbol denotes load per unit length or total load. Many texts use w for intensity (force per length) and W for total load. This question explicitly states W is the total load acting over the span L.


Given Data / Assumptions:

  • Simply supported beam, span L.
  • Total uniformly distributed load W across the span.
  • Static equilibrium and small deflection theory.


Concept / Approach:

For a UDL of intensity w (force per unit length), the maximum bending moment is M_max = wL^2/8 at mid-span. If W is the total load, then W = wL, so M_max = (W/L)L^2/8 = WL/8.


Step-by-Step Solution:

Given W_total = W = wL ⇒ w = W / L.Standard result: M_max = wL^2 / 8.Substitute: M_max = (W/L)L^2 / 8 = WL / 8.


Verification / Alternative check:

Shear at mid-span is zero; bending moment diagram is parabolic, peaking at mid-span with the stated value, consistent with classical solutions.


Why Other Options Are Wrong:

  • W L / 4 doubles the correct value.
  • W L^2 / 8 corresponds to using W as w (confusing total with intensity).
  • W^2 L / 8 and W/(8L) have incorrect dimensions.


Common Pitfalls:

  • Mixing symbols W and w; remember W = w*L for a uniform distribution.


Final Answer:

M = W L / 8.

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