Simply supported beam of span L under a uniformly distributed load (total load notation) A simply supported beam of clear span L carries a uniformly distributed load whose total magnitude over the span is W. What is the maximum bending moment M (sagging) in the beam?
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AM = W L / 8
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BM = W L / 4
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CM = W L^2 / 8
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DM = W^2 L / 8
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EM = W / (8L)
Answer
Correct Answer: M = W L / 8
Explanation
Introduction / Context:The maximum bending moment for a simply supported beam under a uniformly distributed load (UDL) depends on whether the symbol denotes load per unit length or total load. Many texts use w for intensity (force per length) and W for total load. This question explicitly states W is the total load acting over the span L.
Given Data / Assumptions:
- Simply supported beam, span L.
- Total uniformly distributed load W across the span.
- Static equilibrium and small deflection theory.
Concept / Approach:
For a UDL of intensity w (force per unit length), the maximum bending moment is M_max = wL^2/8 at mid-span. If W is the total load, then W = wL, so M_max = (W/L)L^2/8 = WL/8.
Step-by-Step Solution:
Given W_total = W = wL ⇒ w = W / L.Standard result: M_max = wL^2 / 8.Substitute: M_max = (W/L)L^2 / 8 = WL / 8.Verification / Alternative check:
Shear at mid-span is zero; bending moment diagram is parabolic, peaking at mid-span with the stated value, consistent with classical solutions.
Why Other Options Are Wrong:
- W L / 4 doubles the correct value.
- W L^2 / 8 corresponds to using W as w (confusing total with intensity).
- W^2 L / 8 and W/(8L) have incorrect dimensions.
Common Pitfalls:
- Mixing symbols W and w; remember W = w*L for a uniform distribution.
Final Answer:
M = W L / 8.