Difficulty: Easy
Correct Answer: depends on the values of R and C
Explanation:
Introduction / Context:The phase relationship between voltage and current in reactive circuits shapes filter characteristics, stability margins, and timing. In a series RC, the resistor and capacitor share the same current but their voltage drops are out of phase. The net phase between the source voltage and current is not constant; it varies with component values and frequency.
Given Data / Assumptions:
Concept / Approach:The series RC impedance is Z = R − j|XC| with |XC| = 1/(ωC). The phase angle φ between total voltage and current satisfies tan(φ) = −|XC|/R. Therefore the magnitude |φ| = arctan(|XC|/R). Changing R, C, or the frequency (which changes |XC|) alters |XC|/R and hence the phase.
Step-by-Step Solution:
Write Z = R − j|XC|.Compute φ = arctan(Im(Z)/Re(Z)) = arctan(−|XC|/R).Observe dependence: |XC| = 1/(ωC), so φ changes with R, C, and ω.Conclude: phase depends on component values (and frequency), not on voltage amplitude.Verification / Alternative check:Limit cases support the conclusion: if R ≫ |XC|, φ ≈ 0° (almost resistive). If |XC| ≫ R, |φ| approaches 90° (dominantly capacitive). Continuous variation between these limits confirms dependence on R and C (via |XC|).
Why Other Options Are Wrong:
equals 0° / 90°: only true in limiting cases, not generally.depends on amplitude: linear passive networks have phase independent of amplitude.fixed at 45°: occurs only when |XC| = R.Common Pitfalls:Confusing individual component voltage phases with the overall source-to-current phase; assuming linear circuits exhibit amplitude-dependent phase shift (they do not).
Final Answer:depends on the values of R and C
Discussion & Comments