Difficulty: Easy
Correct Answer: 200 kΩ
Explanation:
Introduction / Context:Combining resistance and reactance magnitudes correctly is crucial to predict current and voltage division in AC networks. For series RC, the total impedance magnitude follows a Pythagorean relationship due to the orthogonality of resistive and reactive components in the complex plane.
Given Data / Assumptions:
Concept / Approach:The complex impedance is Z = R − j|XC|. The magnitude is |Z| = sqrt(R^2 + |XC|^2). The numbers 120 and 160 form a 3–4–5 multiple (since 12–16–20 scales to 3–4–5), which simplifies the square root.
Step-by-Step Solution:
Compute squares: 120^2 = 14,400; 160^2 = 25,600 (units kΩ^2).Sum: 14,400 + 25,600 = 40,000.Square root: sqrt(40,000) = 200 (kΩ preserved from magnitudes).Therefore, |Z| = 200 kΩ.Verification / Alternative check:Recognize 12–16–20 as the 3–4–5 family scaled by 4; multiply by 10 to reach 120–160–200. The Pythagorean identity confirms the result immediately without calculator use.
Why Other Options Are Wrong:
280 kΩ: arithmetic (R + |XC|) sum, not vector sum.120 kΩ / 160 kΩ: represent only one leg, not the hypotenuse.40 kΩ: unrelated; perhaps a misread of the squared sum.Common Pitfalls:Adding impedances as scalars; forgetting unit consistency (kΩ vs. Ω); ignoring that reactance contributes orthogonally to resistance.
Final Answer:200 kΩ
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