Impedance of a series RC from given R and XC magnitudes A series RC circuit has resistance R = 120 kΩ and capacitive reactance magnitude |XC| = 160 kΩ at the operating frequency. What is the magnitude of the total impedance?

Difficulty: Easy

Correct Answer: 200 kΩ

Explanation:


Introduction / Context:
Combining resistance and reactance magnitudes correctly is crucial to predict current and voltage division in AC networks. For series RC, the total impedance magnitude follows a Pythagorean relationship due to the orthogonality of resistive and reactive components in the complex plane.



Given Data / Assumptions:

  • R = 120 kΩ.
  • |XC| = 160 kΩ.
  • Series connection under sinusoidal excitation.
  • We seek |Z|, not the phase angle (though it can be found as arctan(|XC|/R)).


Concept / Approach:
The complex impedance is Z = R − j|XC|. The magnitude is |Z| = sqrt(R^2 + |XC|^2). The numbers 120 and 160 form a 3–4–5 multiple (since 12–16–20 scales to 3–4–5), which simplifies the square root.



Step-by-Step Solution:

Compute squares: 120^2 = 14,400; 160^2 = 25,600 (units kΩ^2).Sum: 14,400 + 25,600 = 40,000.Square root: sqrt(40,000) = 200 (kΩ preserved from magnitudes).Therefore, |Z| = 200 kΩ.


Verification / Alternative check:
Recognize 12–16–20 as the 3–4–5 family scaled by 4; multiply by 10 to reach 120–160–200. The Pythagorean identity confirms the result immediately without calculator use.



Why Other Options Are Wrong:

280 kΩ: arithmetic (R + |XC|) sum, not vector sum.120 kΩ / 160 kΩ: represent only one leg, not the hypotenuse.40 kΩ: unrelated; perhaps a misread of the squared sum.


Common Pitfalls:
Adding impedances as scalars; forgetting unit consistency (kΩ vs. Ω); ignoring that reactance contributes orthogonally to resistance.



Final Answer:
200 kΩ

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