Series network of discrete resistors: three resistors 120 Ω, 270 Ω, and 330 Ω are connected in series. What is the total equivalent resistance of the series combination?

Introduction / Context:
In a series circuit, resistances add directly because the same current flows through each element and voltage drops sum. Recognizing this rule is foundational for quickly computing totals and distributing voltages with the voltage-divider principle.

Given Data / Assumptions:

• R₁ = 120 Ω, R₂ = 270 Ω, R₃ = 330 Ω.
• Series connection (same current through all).
• We seek R_total.

Concept / Approach:

For series resistors, R_total = R₁ + R₂ + R₃. There is no averaging or product; simple arithmetic addition applies. The result must be greater than any individual resistor value.

Step-by-Step Solution:

Verification / Alternative check:

Since each term is positive, the total exceeds the largest single resistor (330 Ω), which is consistent with series addition.

Why Other Options Are Wrong:

Less than 120 Ω contradicts series addition. The average is not a series rule. 120 Ω is only one component, not the total.

Common Pitfalls:

Confusing series with parallel (where reciprocals add and the total is less than any individual branch); mis-adding values.

Final Answer:

720 Ω