Find the missing series element: A series circuit has three resistors. Two resistors are 1.2 kΩ each, and the total resistance is 12 kΩ. What is the value of the third resistor?

Introduction / Context:Solving for an unknown in a series network is a direct application of the additive property of resistances. This is common when back-calculating a missing component from a measured total or when designing a target equivalent resistance from available parts.

Given Data / Assumptions:

• Total series resistance: 12 kΩ.
• Two known resistors: 1.2 kΩ and 1.2 kΩ.
• All are simple linear resistors in series.

Concept / Approach:For series resistors, R_total = R1 + R2 + R3. Rearrange to find the unknown: R3 = R_total − (R1 + R2). Keep units consistent, then convert back to a convenient expression (ohms or kilo-ohms) as needed.

Step-by-Step Solution:

Verification / Alternative check:Add them back: 1.2 kΩ + 1.2 kΩ + 9.6 kΩ = 12.0 kΩ exactly. The arithmetic closes perfectly, confirming the result.

Why Other Options Are Wrong:

• is 960 Ω or is 1.2 kΩ: Far too small; their sum with the two 1.2 kΩ parts would not reach 12 kΩ.
• cannot be determined: Incorrect; the series sum uniquely determines the missing value.

Common Pitfalls:

• Mixing kilo-ohms and ohms without conversion, causing factor-of-1000 mistakes.
• Subtracting only one of the known resistors from the total instead of both.

Final Answer:is 9,600 Ω