Uniform series current: Five resistors are connected in one series path. If 3 A enters the first resistor, how much current enters the second resistor in the same circuit?

Introduction / Context:
A hallmark of series circuits is that the same current flows through each component because there is only one path for charge. This quick concept check ensures you can reason about current distribution without unnecessary calculations.

Given Data / Assumptions:

• Five resistors connected strictly in series.
• Measured current entering the first resistor: 3 A.
• Ideal wires and elements; DC steady state.

Concept / Approach:
In series, current continuity applies: the current that enters one element must leave it and enter the next, as there is no branching. Therefore, the current into every resistor is identical to the loop current.

Step-by-Step Solution:

Verification / Alternative check:
Kirchhoff’s current law at the node between the first and second resistors: the current leaving the first equals the current entering the second, hence 3 A continues unchanged.

Why Other Options Are Wrong:

• 1 A, 0.3 A: Would require a branch or time-varying storage element changing current, not present here.
• 4 A: Would violate current continuity in a single series path.

Common Pitfalls:

• Confusing series circuits with parallel circuits where current divides.
• Assuming current diminishes across elements; voltage divides, not current, in series.

Final Answer:
3 A