Void ratio from saturation condition: A saturated soil has water content w = 40% and specific gravity of solids G = 2.7. Determine the void ratio e (assume full saturation).

Difficulty: Easy

Correct Answer: 1.08

Explanation:


Introduction / Context:
For fully saturated soils, a very useful identity links void ratio e, water content w, and specific gravity G. This provides a quick check on laboratory data and helps initialize consolidation and seepage analyses.


Given Data / Assumptions:

  • Saturation: S_r = 1.0 (fully saturated).
  • Water content w = 40% = 0.40 (decimal).
  • Specific gravity of solids G = 2.7.


Concept / Approach:
Under full saturation, the fundamental phase-relationship reduces to e = w * G (with w in decimal form). This comes from S_r = (w * G)/e and S_r = 1 at saturation, giving e = w * G directly.


Step-by-Step Solution:

Use S_r = (w * G) / e with S_r = 1.Therefore e = w * G.Substitute: e = 0.40 * 2.7 = 1.08.


Verification / Alternative check:
Porosity n = e / (1 + e) = 1.08 / 2.08 ≈ 0.519 (~52%), a realistic value for saturated fine-grained soils at this water content and mineral density.


Why Other Options Are Wrong:

  • 0.40 or 0.52 or 0.80: Do not satisfy e = w * G for the given data.
  • “None of these”: incorrect because a valid computed value exists in the options.


Common Pitfalls:
Using w as a percent without converting to decimal; confusing G (dimensionless) with unit weights.


Final Answer:
1.08

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