Difficulty: Medium
Correct Answer: D = 0.278 * V * t + V^2 / (254 * (f ± G))
Explanation:
Introduction / Context:
Stopping Sight Distance (SSD) is the minimum visible distance required for a driver to perceive, react, and bring the vehicle to a stop safely. The SSD expression combines the distance traveled during perception-reaction and the braking distance on a given grade.
Given Data / Assumptions:
Concept / Approach:
SSD has two parts: perception-reaction distance and braking distance. Perception-reaction distance equals speed in m/s times t. Braking distance follows energy and friction–grade balance, which, with unit conversions, gives the 254 constant when V is in km/h.
Step-by-Step Solution:
Verification / Alternative check:
On level grade (G = 0), the formula reduces to D = 0.278 * V * t + V^2 / (254 * f), matching standard design tables.
Why Other Options Are Wrong:
Options B, C, D distort units and physical meaning. Option E omits braking distance and is therefore incomplete.
Common Pitfalls:
Using grade in the wrong sign or units; forgetting that adverse downgrade increases SSD, while upgrade reduces it.
Final Answer:
D = 0.278 * V * t + V^2 / (254 * (f ± G))
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