Use resistor color code and Ohm’s law: a resistor marked red–orange–orange–silver is connected across a 50 V source; determine the current through the resistor (choose the closest standard value).

Difficulty: Medium

Correct Answer: 2.2 mA

Explanation:


Introduction / Context:
Reading resistor values from color bands and then applying Ohm’s law is a staple lab task. The 4-band code uses two significant digits, a multiplier, and a tolerance band. After decoding resistance, Ohm’s law gives the current for a given applied voltage.


Given Data / Assumptions:

  • Color code: red, orange, orange, silver.
  • Supply: 50 V DC (or RMS equivalent for a purely resistive case).
  • Assume nominal resistance for current calculation.


Concept / Approach:

Decode colors: first digit, second digit, multiplier, tolerance. Compute R, then use I = V / R. Round to the nearest provided option as typical in multiple-choice problems when exact values fall between discrete choices.


Step-by-Step Solution:

Decode digits: red = 2 (first), orange = 3 (second) → 23.Multiplier: orange = × 10^3 → R = 23 × 10^3 Ω = 23 kΩ.Tolerance: silver = ±10% (not needed for nominal current).Compute current: I = V / R = 50 / 23,000 ≈ 0.0021739 A ≈ 2.17 mA.Nearest choice: 2.2 mA.


Verification / Alternative check:

Even at ±10% tolerance, the nominal reading remains closest to 2.2 mA among options (range approx. 1.95–2.41 mA).


Why Other Options Are Wrong:

2 mA is less precise than 2.2 mA to the nominal calculation; 21.4 mA and 214 mA are off by an order of magnitude or more for 23 kΩ at 50 V.


Common Pitfalls:

Misreading color positions; confusing the orange multiplier with × 10^2; forgetting to convert kΩ to Ω before applying V / R.


Final Answer:

2.2 mA

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